How to pass argument in java

Question

Hi i am using this code to run the shell script.the thing is i want to pass argument "trng-java" while i am running program.like this

like java Classname trng-java

code:

import java.io.*;

public class Test
{


public static void main(String[] args)
{
    try {
        Runtime rt = Runtime.getRuntime();
        Process pr = rt.exec(new String[]{"/bin/sh", "/tmp/test.sh", "trng-java"});

        BufferedReader input = new BufferedReader(new InputStreamReader(pr.getInputStream()));
        String line = "";
        while ((line = input.readLine()) != null) {
            System.out.println(line);
        }
    } 
    catch (Exception e) {
        System.out.println(e.toString());
        e.printStackTrace();
    }
}
}

How to do this?

You mean accept it as input to your program? It's in the args array that's the parameter of main. — Rup
– Rup, Commented Jun 3, 2013 at 12:28

Jakob · Accepted Answer · 2013-06-03 12:29:56Z

5

The argument you pass in will be found in the args parameters as String yourParam = args[0]

answered Jun 3, 2013 at 12:29

Jakob

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Comments

Simon Curd · Accepted Answer · 2013-06-03 12:31:33Z

3

Command line arguments are passed to your application in the String[] parameter args, so you should be able to access the value using args[0].

Process pr = rt.exec(new String[]{"/bin/sh", "/tmp/test.sh", args[0] });

answered Jun 3, 2013 at 12:31

Simon Curd

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gma · Accepted Answer · 2013-06-03 12:32:00Z

2

Process pr = rt.exec(new String[]{"/bin/sh", "/tmp/test.sh", args[0]});

Of course, you will also need to check that args contains at least one argument

answered Jun 3, 2013 at 12:32

gma

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Μenelaοs · Accepted Answer · 2013-06-03 12:33:33Z

When you pass arguments to a java application, they are accessible through the args[] array in main.

See: http://docs.oracle.com/javase/tutorial/essential/environment/cmdLineArgs.html which I am quoting:

Echoing Command-Line Arguments

The Echo example displays each of its command-line arguments on a line by itself:
public class Echo {
    public static void main (String[] args) {
        for (String s: args) {
            System.out.println(s);
        }
    }
}
The following example shows how a user might run Echo. User input is in italics.
java Echo Drink Hot Java
Drink
Hot
Java
Parsing Numeric Command-Line Arguments

If an application needs to support a numeric command-line argument, it must convert a String argument that represents a number, such as "34", to a numeric value. Here is a code snippet that converts a command-line argument to an int:
int firstArg;
if (args.length > 0) {
    try {
        firstArg = Integer.parseInt(args[0]);
    } catch (NumberFormatException e) {
        System.err.println("Argument" + " must be an integer");
        System.exit(1);
    }
}

michael667 · Accepted Answer · 2013-06-03 12:31:24Z

0

Just add the argument(s) to your command, like this:

rt.exec("/bin/sh /tmp/test.sh trng-java");

answered Jun 3, 2013 at 12:31

michael667

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Comments

stinepike · Accepted Answer · 2013-06-03 12:31:42Z

0

in public static void main(String[] args) the args parameter is the arguement. If you use multiple arguement like

java Classname a b c

Then in your main method args will be an array containing a,b,c

if this is what you want then args[0] is the preferred arguement.

answered Jun 3, 2013 at 12:31

stinepike

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