Add query parameters to a GetMethod (using Java commons-httpclient)?

Question

I followed this other SO question to set parameter for the URL but it was giving error:

The method setQueryString(String) in the type HttpMethodBase is not applicable for the arguments (NameValuePair[])

and

Cannot instantiate the type NameValuePair.

I am not able to understand the actual problem. Could some one help me on this?

The code I have used from the above question

GetMethod method = new GetMethod("example.com/page";); 
method.setQueryString(new NameValuePair[] { 
    new NameValuePair("key", "value") 
});

Did u remove the superfluous semi-colon here "example.com/page"; — vikingsteve
– vikingsteve, Commented Apr 26, 2013 at 7:43
Are you using httpclient 3.x or 4.x? The example you give is typical 3.x code, not 4.x. — NilsH
– NilsH, Commented Apr 26, 2013 at 7:43
Vikingsteve removed that semi-colon already when excuting the code — Java Questions
– Java Questions, Commented Apr 26, 2013 at 7:46
Great NilsH i am using 4.x.:). How to set parameters when using 4.x ? — Java Questions
– Java Questions, Commented Apr 26, 2013 at 7:46
@Anto sure? There is no GetMethod class in 4.x version. According to javadoc it is HttpGet — Vasyl Keretsman
– Vasyl Keretsman, Commented Apr 26, 2013 at 7:47

NilsH · Accepted Answer · 2013-04-26 07:52:41Z

14

In HttpClient 4.x, there is no GetMethod anymore. Instead there is HttpGet. Quoting an example from the tutorial:

Query parameters in the url:

HttpGet httpget = new HttpGet(
 "http://www.google.com/search?hl=en&q=httpclient&btnG=Google+Search&aq=f&oq=");

Creating the query string programatically:

URIBuilder builder = new URIBuilder();
builder.setScheme("http").setHost("www.google.com").setPath("/search")
    .setParameter("q", "httpclient")
    .setParameter("btnG", "Google Search")
    .setParameter("aq", "f")
    .setParameter("oq", "");
URI uri = builder.build();
HttpGet httpget = new HttpGet(uri);
System.out.println(httpget.getURI());

answered Apr 26, 2013 at 7:52

NilsH

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2 Comments

NilsH Over a year ago

I should also add that httpclient 4.x and httpclient 3.x have quite different APIs. Examples you find for httpclient 3.x will most likely not work with 4.x.

Daniil Shevelev Over a year ago

I am trying to use HTTPclient 4.2.5 with SalesForce REST API and it does not work - setting parameter results in an error page, while using "setQueryString" with 3.1 API results in JSON... Any clues?

pancho.gb.cu · Accepted Answer · 2014-07-09 22:50:03Z

1

Interfaces can not be directly instantiated, you should instantiate classes that implements such Interfaces.

Try this:

NameValuePair[] params = new BasicNameValuePair[] {
        new BasicNameValuePair("param1", param1),
        new BasicNameValuePair("param2", param2),
};

answered Jul 9, 2014 at 22:50

pancho.gb.cu

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Comments

Anurag Tripathi · Accepted Answer · 2013-04-26 10:10:53Z

0

You can pass query parameter within the the url.

String uri = "example.com/page?key=value";
HttpClient httpClient = new DefaultHttpClient();
HttpGet method = new HttpGet(url);
HttpResponse httpResponse = httpClient.execute(method);
BufferedReader br = new BufferedReader(new InputStreamReader(httpResponse.getEntity().getContent()));
String content="", line;
while ((line = br.readLine()) != null) {
     content = content + line;
}
System.out.print(content);

edited Apr 26, 2013 at 10:10

answered Apr 26, 2013 at 7:49

Anurag Tripathi

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2 Comments

Java Questions Over a year ago

There is no GetMethod in the version i have used, Please have a look at the comments i have provided

Anurag Tripathi Over a year ago

I changed my answer according to your httpclient 4.x

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