I have a python code like
for i in re.finditer('something(.+?)"', html):
I am now trying to find out how many times its going to loop before going to that loop..in other words the length of array i. Could anyone give me an alternative but similar code with with I get length of the loop.
x = list(re.finditer('something(.+?)"', html))
if len(x)
....
for i in x:
....
findall is not an adequate replacement since it returns strings, not match objects.
You can't do that with re.finditer because it returns an iterator which doesn't know when it's finished until it does (since it finds the next match on each iteration) ..., you'll have to use re.findall.
matches = re.findall('something(.+?)"', html)
num_loops = len(matches)
or use @thg435's approach if you do in fact need the match objects.
len(..) on the list. If you want the index number for each match then do for i, m in enumerate(re.findall(...))finditer returns the results as it finds them. There is no way finditer can tell you how many times you will loop in advance.
You need to use something else. Either re.findall or possibly re.search to get the length
