Add values to end of multidimensional array

Question

I have an array of arrays and I want to be able to add values to the array every time a user hits the add button.

var transactions = [];
transactions[0] = []; // holds date
transactions[1] = []; // holds transaction type
transactions[2] = []; // holds amount


transactions[0][i] = $("date").value;
transactions[1][i] = $("transType").value;
transactions[2][i] = parseFloat( $("amount").value);

these are the snippets . . . I realize I need to work on validation (which I will do) at this point I'm more concerned with loading the arrays. The problem is the method I'm familiar with works with 1-dimensional arrays and I don't know how to replace it.

in short is it possible to reproduce this:

transactions[transactions.length] = $("date").value;

for a multidimensional array.

Thank You

disregard the [i] that was an attempt using a counter

user2101459
– user2101459

2013-03-01 21:16:10 +00:00
Commented Mar 1, 2013 at 21:16 — user2101459
– user2101459, Commented Mar 1, 2013 at 21:16

Ricardo Lohmann · Accepted Answer · 2013-03-01 21:16:07Z

1

Use push:

transactions[0].push( $("date").value );

answered Mar 1, 2013 at 21:16

Ricardo Lohmann

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Comments

LoveAndCoding · Accepted Answer · 2013-03-01 21:16:35Z

1

You're looking for the Array.push() method. It allows you to push values on to the end of an array.

For your use case, you can do that on both levels of the array. See below:

var transactions = [];
transactions.push([]);
transactions.push([]);

transactions[0].push( $('date').value );

answered Mar 1, 2013 at 21:16

LoveAndCoding

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VisioN · Accepted Answer · 2013-03-01 21:17:02Z

1

There is no problem for using the same approach:

transactions[0][transactions[0].length] = $("date").value;

or with push method:

transactions[0].push($("date").value);

... keeping in mind that you've initialized transactions[0] with empty array [].

answered Mar 1, 2013 at 21:17

VisioN

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Sam · Accepted Answer · 2013-03-01 21:17:30Z

0

Yes, just idem for multidimensional

transactions[0][transactions[0].length] = var1;

answered Mar 1, 2013 at 21:17

Sam

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James · Accepted Answer · 2013-03-01 22:58:25Z

0

Seems a little weird you are doing:

[[array of transaction dates],[array of transaction types],[array of transaction amounts]]

Are you sure you don't want

[array of transactions, with date,type,amount properties]

?

var transactions = [];
transactions.push({'date': $("date").value, 'type': $("transType").value, 'amount': parseFloat( $("amount").value)});

var i = 0;

alert('date ' + transactions[i].date + ' type ' + transactions[i].type + ' amount ' + transactions[i].amount);

answered Mar 1, 2013 at 22:58

James

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