How to get name of called method (added dynamically) in Python?

Question

I have class:

class SimpleClass:
    def __init__(self):
        pass

    def init_levels(self):
        levels = get_levels_list()
        for level in levels:
            Transplant(foo, Simplelog, method_name=level)

Transplant is a class for dynamically adding methods to class:

class Transplant:
    def __init__(self, method, host, method_name=None):
        self.host = host
        self.method = method
        self.method_name = method_name
        setattr(host, method_name or method.__name__, self)

    def __call__(self, *args, **kwargs):
        nargs = [self.host]
        nargs.extend(args)
        return apply(self.method, nargs, kwargs)

Foo is a function for "transplanting":

def foo(self):
    return

How can I get called method name inside foo?

For example I execute:

simpleinst = SimpleClass()
simpleinst.init_levels()

How can I modify my code for getting called method name in foo definition body?

Martijn Pieters · Accepted Answer · 2013-02-04 11:19:26Z

2

You'll have to pass it in explicitly:

class Transplant:
    def __init__(self, method, host, method_name=None):
        self.host = host
        self.method = method
        self.method_name = method_name or method.__name__
        setattr(host, method_name or method.__name__, self)

    def __call__(self, *args, **kwargs):
        nargs = [self.host, self.method_name]
        nargs.extend(args)
        return apply(self.method, nargs, kwargs)

and extend foo to accept that as an argument.

answered Feb 4, 2013 at 11:19

Martijn Pieters

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1 Comment

CuriousD Over a year ago

Thank! I just replace nargs = [self.host] to nargs = [self] and now I have all method parameters.

danodonovan · Accepted Answer · 2013-02-04 11:14:58Z

1

Have you looked at getattr?

getattr(self, "method")

answered Feb 4, 2013 at 11:14

danodonovan

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Comments

unutbu · Accepted Answer · 2013-02-04 11:17:48Z

0

You could do it with a function factory, make_foo:

The key step is redefining the function's func_name attribute:

foo.func_name = name

class SimpleClass:
    def init_levels(self):
        levels = ['foo', 'bar']
        for level in levels:
            # Your original code defined this on `SimpleLog`. Did you mean `SimpleClass`?
            setattr(SimpleClass, level, make_foo(level))

def make_foo(name):
    def foo(self):
        print('{n} has been called'.format(n = foo.func_name))

    foo.func_name = name
    return foo

simpleinst = SimpleClass()
simpleinst.init_levels()
simpleinst.foo()
# foo has been called
simpleinst.bar()
# bar has been called

answered Feb 4, 2013 at 11:17

unutbu

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