How to get array value as return value on curl php request?

Question

I am having hard time using curl PHP as I am new to PHP. The problem is that I am not getting any return value from a curl request. There is a remote file I am accessing which has this code:

test.php:

$test->getCall();
public function getCall() {
  $var = array('fname'=>'jack','lname'=>'williams');
  return $var;
}

The script from which I am making the call.

requestVal.php

try{
  $ch = curl_init();
  if (FALSE === $ch){
    throw new Exception('failed to initialize');
  }
  curl_setopt($ch, CURLOPT_URL,"http://www.xyz.com/app/src/test.php");
  curl_setopt($ch, CURLOPT_POST, TRUE);
  curl_setopt($ch, CURLOPT_POSTFIELDS, $msg);
  curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE);
  curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);
  $p_result = curl_exec($ch);
  var_dump($p_result);
  print_r($p_result);
  if (FALSE === $p_result) {
    throw new Exception(curl_error(), curl_errno());
    curl_close($ch);
  } else{
    curl_close($ch);
    return $p_result;
  }
}catch(Exception $e) {
  trigger_error(sprintf('Curl failed with error #%d: %s',$e->getCode(), $e->getMessage()),E_USER_ERROR);
}

I don't get any value in $p_result nor an exception curl_error().

in actual code yes, and i call it by its object which $test in this case — user1371033
– user1371033, Commented Dec 2, 2012 at 2:04
Your problem is not curl in PHP. Instead fix the script first that should return something and test it without the scond PHP script. Curl will only take (as text) what the script your request with curl does return. So test the return value of the script first and then you will find your actual error. Asking for PHP curl here is not constructive so, it's just the wrong end. So do some basic debugging first and you should be able to see more clear. E.g. request test.php with the curl commandline client and see the output. Always a useful tool to have at hand. — hakre
– hakre, Commented Dec 2, 2012 at 12:49

Ranty · Accepted Answer · 2012-12-02 19:51:08Z

15

No matter what you echo in your test.php, curl will read it as a String. In your case, you echo nothing. You call a function that returns the array, but you don't print the array, so nothing is sent to output. If you want to get the same array in requestVal.php after curl request, you need to encode it in some way, I would suggest JSON as it's easy to start with. For a quick example, in place of $test->getCall(); you could do:

echo json_encode($test->getCall());

And in requestVal.php:

$array = json_decode(trim($p_result), TRUE);
print_r($array);

You can find each function description at php.net.

answered Dec 2, 2012 at 19:51

Ranty

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Cyprian · Accepted Answer · 2012-12-02 14:49:43Z

1

If you are using curl you should expect exactly the same result as you'll get if you run your test.php script in any browser. So, if your test.php is like:

echo "123";

in your browser you'll see "123" and that's also you'll get inside your $p_result variable. If your test.php is like:

function foo() {
    return "123";
}

foo();

You see nothing in browser and get nothing in your $p_result as well.

So, try change your test.php in something like that:

public function getCall() {
    $var = array('fname'=>'jack','lname'=>'williams');
    return $var;
}

var_dump($test->getCall()); // of course you will show these values in better way (depends on your needs)

answered Dec 2, 2012 at 14:49

Cyprian

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Comments

Imran Nababan · Accepted Answer · 2013-11-22 06:48:23Z

0

like Ranty said, you can return a string at test.php code

$test->getCall();
public function getCall() {
  $var = array('fname'=>'jack','lname'=>'williams');
  echo serialize($var);
}

So, you can caught a serialization data at requestVal.php code, by unserialize data from remote server

unserialize($content)

edited Nov 22, 2013 at 6:48

answered Nov 22, 2013 at 6:24

Imran Nababan

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