Acessing The Return Array

Question

edit:

<?php
    $file= 'fbplus.jpg';

    $args = array(
       'message' => $album_message,
    );
    $args[basename($file)] = '@' . realpath($file);
    $ch = curl_init();
    $url = $graph_url;
    curl_setopt($ch, CURLOPT_URL, $url);
    curl_setopt($ch, CURLOPT_HEADER, false);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
    curl_setopt($ch, CURLOPT_POST, true);
    curl_setopt($ch, CURLOPT_POSTFIELDS, $args);
    $data = curl_exec($ch);
    //returns the photo id
    print_r(json_decode($data,true));


    echo "$data['id'] "; //wont work
        echo "$data[id] "; //wont work


?>

this was the return, after i successfully uploaded a photo.

Array ( [id] => 112235735579158 [post_id] => 100003781972892_112203478915717 )

Isn't that an assoc. array? Should be $data['id'] instead of $data[id] — Smamatti
– Smamatti, Commented Apr 28, 2012 at 10:48
If that is the array, then $data['id'] should work. Also, please use long open tags. Later down the road when you're stuck on a server that doesn't have short open tags enabled, you'll likely regret it. — Corbin
– Corbin, Commented Apr 28, 2012 at 10:49
@Smamatti, yes, syntactically, id should be in quotes, but that's not what's causing the problem here. — Nadh
– Nadh, Commented Apr 28, 2012 at 10:49
@jcubic, short_open_tag (<? ?>) is deprecated, and was removed in PHP 5.3.0 — Nadh
– Nadh, Commented Apr 28, 2012 at 10:58

Nadh · Accepted Answer · 2012-04-28 11:09:50Z

2

curl_exec() returns a string (contents of the webpage), not an Array. So you cannot do $data['id'] because $data is a string and not an array.

What is the url you are posting to? What is its exact output?

EDIT: Looks like the url returns JSON. In that case:

<?php
    $file= 'fbplus.jpg';

    $args = array(
       'message' => $album_message,
    );
    $args[basename($file)] = '@' . realpath($file);
    $ch = curl_init();
    $url = $graph_url;
    curl_setopt($ch, CURLOPT_URL, $url);
    curl_setopt($ch, CURLOPT_HEADER, false);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
    curl_setopt($ch, CURLOPT_POST, true);
    curl_setopt($ch, CURLOPT_POSTFIELDS, $args);
    $data = curl_exec($ch);
    //returns the photo id

    $data = json_decode($data,true);

    echo $data['id'];
?>

edited Apr 28, 2012 at 11:09

answered Apr 28, 2012 at 10:48

Nadh

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5 Comments

Roxy Gutera Over a year ago

i used this print_r(json_decode($data,true)); the output is Array ( [id] => 112265748909490 [post_id] => 100003781972892_112203478915717 ) . then why is it an array?

Nadh Over a year ago

Ah, it's an array because you are using json_decode() which you did not mention in your original question.

Nadh Over a year ago

@RoxyGutera, I've edited my answer with code that works. While you are doing a json_decode() inside print_r(), you are not assigning it to the $data variable!

Roxy Gutera Over a year ago

the output is { (one curly brace) . whats happening?

Roxy Gutera Over a year ago

sorry about that i forgot to remove the print_r. thanks NADH it worked

Diogo Raminhos · Accepted Answer · 2012-04-28 10:49:47Z

0

Are you accessing the Facebook Graph API?

If so just use:

$data = json_decode($data);

and the you can access it trough $data->id

answered Apr 28, 2012 at 10:49

Diogo Raminhos

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2 Comments

Roxy Gutera Over a year ago

that was my first approach but still $data->id is NULL. yes graph api and $data = json_decode($data); is in my code already. but still i cant access the array

Nadh Over a year ago

@Roxy, by default, json_decode() returns an object. If you want to get an array, try json_decode($data, true)

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