How can I get the path of my python script?

Question

I am trying to get the path of my python script.

I know 'sys.argv[0] gives me the path and the name of my python script.

how can I just get the path?

I tried:

 print sys.argv[0]
    path = sys.argv[0].split("/")
    scriptpath = "".join(path[0:-1])

But it does not add back the path separator.

change "".join(path[0:-1]) to "/".join(path[0:-1]) if you had to have that specific solution for whatever reason :) — Jason Sperske
– Jason Sperske, Commented Nov 21, 2012 at 23:19

wim · Accepted Answer · 2012-11-21 23:37:15Z

8

Prefer to use __file__, like this:

os.path.dirname(os.path.realpath(__file__))

Note: using sys.argv[0] may not work if you call the script via another script from another directory.

answered Nov 21, 2012 at 23:37

wim

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1 Comment

Christoph Jüngling Over a year ago

Unfortunately this one doesn't work as intended, if you use PyInstaller, because it is unpacked into a temporary folder which then is (correctly) returned as the path of the __file__. In this case dirname(realpath(sys.argv[0])) works fine.

SingleNegationElimination · Accepted Answer · 2012-11-21 23:17:06Z

3

you're looking for os.path.dirname(), in case you might have a relative pathame, you need os.path.abspath() too

answered Nov 21, 2012 at 23:17

SingleNegationElimination

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Comments

Michael · Accepted Answer · 2012-11-21 23:18:02Z

1

Don't try string operations on paths, use the os.path module instead. E.g.:

scriptpath = os.path.dirname(sys.argv[0])

answered Nov 21, 2012 at 23:18

Michael

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Community · Accepted Answer · 2017-05-23 11:46:25Z

0

From another Stackoverflow thread

import sys, os

print 'sys.argv[0] =', sys.argv[0]             
pathname = os.path.dirname(sys.argv[0])        
print 'path =', pathname
print 'full path =', os.path.abspath(pathname)

edited May 23, 2017 at 11:46

CommunityBot

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answered Nov 21, 2012 at 23:20

aw4lly

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