calling a blocking method call with timeout in java

Question

I want to call a method in java which blocks for some reason. I want to wait for the method for X minutes and then I want to stop that method.

I have read one solution here on StackOverflow which gave me a first quick start. I am writing that here :-

ExecutorService executor = Executors.newCachedThreadPool();
    Callable<Object> task = new Callable<Object>() {
       public Object call() {
          return something.blockingMethod();
       }
    };
    Future<Object> future = executor.submit(task);
    try {
       Object result = future.get(5, TimeUnit.SECONDS); 
    } catch (TimeoutException ex) {
       // handle the timeout
    } catch (InterruptedException e) {
       // handle the interrupts
    } catch (ExecutionException e) {
       // handle other exceptions
    } finally {
       future.cancel(); // may or may not desire this
    }

But now my problem is, my function can throw some Exception which I have to catch and do some task accordingly. So if in code the function blockingMethod() thorws some exception how do I catch them in Outer class ?

I would catch it in the anoymous class. This way there is no exception to catch. — Peter Lawrey
– Peter Lawrey, Commented Jul 6, 2012 at 13:15
Also, don't explicitly catch each and every checked exception because you're probably not going to write any specific handling code. Just write catch (RuntimeException e) { throw e; } catch (Exception e) { throw new RuntimeException(e); } — Marko Topolnik
– Marko Topolnik, Commented Jul 6, 2012 at 13:24
Yes Earlier I thought same thing, I would have done that but there are lots of variable of outer class which I wanted to use in exception handling code. And I am not able to access those variables in Inner class. — vikas ramnani
– vikas ramnani, Commented Jul 6, 2012 at 13:32

Keppil · Accepted Answer · 2012-07-06 13:32:40Z

4

You have everything set up to do that in the code you provide. Just replace

// handle other exceptions

with your exception handling.
If you need to get your specific Exception you get it with:

Throwable t = e.getCause();

And to differentiate between your Exceptions you can do like this:

if (t instanceof MyException1) {
  ...
} else if (t instanceof MyException2) {
  ...
...

edited Jul 6, 2012 at 13:32

answered Jul 6, 2012 at 13:14

Keppil

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1 Comment

vikas ramnani Over a year ago

I did not know that I will do that for sure :) Just one more question, if I have different types of Exception for Example MyException1, MyException2 and I have to different treatments according to different Exception. How do I differentiate between multiple Exceptions ?

gkuzmin · Accepted Answer · 2012-07-06 13:11:57Z

1

In cause of ExecutionException instance, I suppose.

answered Jul 6, 2012 at 13:11

gkuzmin

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MattAllegro · Accepted Answer · 2019-06-29 11:48:45Z

1

In the ExecutionException catch block: e.getCause()

https://docs.oracle.com/javase/6/docs/api/java/lang/Throwable.html#getCause

edited Jun 29, 2019 at 11:48

MattAllegro

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answered Jul 6, 2012 at 13:14

neyb

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Matt Westlake · Accepted Answer · 2012-07-06 13:14:59Z

-1

thread.sleep(x millisecods) will stop the thread for x milliseconds, then it will resume. The other way to do it is to call thread.wait(x) (with a timeout value for x) and then call thread.notify() to "wake" the sleeping thread.

answered Jul 6, 2012 at 13:14

Matt Westlake

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