So I have, let's say
float x;
and I have
LPCWSTR message=L"X is";
how can I create a LPCWSTR with the message
"X is [x]"
?
-
Do you have access to the STL? You could use a wstringstreampstrjds– pstrjds2012-05-31 13:42:47 +00:00Commented May 31, 2012 at 13:42
-
@pstrjds: Pedantry -- streams are not part of the STL. They are part of the Standard Library.John Dibling– John Dibling2012-05-31 14:21:56 +00:00Commented May 31, 2012 at 14:21
-
@JohnDibling - I stand corrected. Thanks for pointing that out.pstrjds– pstrjds2012-05-31 14:57:00 +00:00Commented May 31, 2012 at 14:57
Add a comment
|
3 Answers
You could use wstringstream:
#include <string>
#include <sstream>
#include <iostream>
int main()
{
float x = 0.1f;
std::wstringstream s;
s << L"X is " << x;
std::wstring ws = s.str();
std::wcout << ws << "\n";
return 0;
}
and create an LPCWSTR from it if required, or just use the std::wstring.
You would use something like wsprintf() or its more modern (and safe) replacement, such as StringCbPrintf().
The point is that you can't just "convert", you need to build the string, character by character, that is the textual representation of the floating-point number.
1 Comment
arx
Or you can use
swprintf which is standard and in recent compilers takes a buffer size parameter so it's also safe.