Invoking a Function by String in JavaScript

Question

After reading many times this question and its accepted answer How to execute a JavaScript function when I have its name as a string

I tried to do it on my own. but I think its my unlucky day today that what I had tried was not working. I created already a fiddle for my testing

//the function I want to invoke by String
function CheckMe() {
    return "haha";
}

//the function that will search for the function and invoke it
function InvokeChecking(func2check) {
    var fn = func2check;
    if (typeof fn === 'function') {
        return = fn(); //invoke the function
    }
}

//the event listener  ( ´ ▽ ` )ﾉ
$("#checker").click(function () {
    alert("event is working");
    alert(InvokeChecking("CheckMe"));
});

http://jsfiddle.net/laupkram/qKHpu/2/

the thing I want to do is to invoke the function I declared by using string and get its return value. So I followed what I saw here in SO using the (fn==='function') argument. but it seems not working for me.

where I went wrong?

NOTE: I already check it in firebug and my function exist... Did I fall in a scoping problem? or something?

please include all relevant parts of your question in your question. — Yoshi
– Yoshi, Commented May 24, 2012 at 8:03
I think I already put the needed parts to understand my question... and there is a fiddle already... — Netorica
– Netorica, Commented May 24, 2012 at 8:04
jsfiddle.net/qKHpu/7 typeof fn is actually string, not function — Andreas Wong
– Andreas Wong, Commented May 24, 2012 at 8:04
@Mahan A link to an external resource does not count as "including". — Yoshi
– Yoshi, Commented May 24, 2012 at 8:05

Ja͢ck · Accepted Answer · 2012-05-24 08:04:55Z

3

A function by name, as the related answer you mentioned says, is invoked by:

var function_name = 'alert';
window[function_name]('hello world');

Comments

Andreas Wong · Accepted Answer · 2012-05-24 08:05:19Z

1

http://jsfiddle.net/qKHpu/8/

You need to pass in the literal name of the function, without quotes ("), otherwise it'll be treated as a literal string, which is meaningless

alert(InvokeChecking(CheckMe)); // instead of alert(InvokeChecking("CheckMe"));

answered May 24, 2012 at 8:05

Andreas Wong

60.7k19 gold badges112 silver badges123 bronze badges

3 Comments

Netorica Over a year ago

sorry... SO is blocking the potato... I won't forget to accept this after 7 mins

Ja͢ck Over a year ago

Strange, not sure who downvoted this answer ... it's also correct =/

Andreas Wong Over a year ago

someone downvote-stalked me :S, 16 seconds after, I got another downvote :(, o well :(

vijaykumar · Accepted Answer · 2012-05-24 08:31:30Z

0

http://jsfiddle.net/qKHpu/27/

check it work some ..

answered May 24, 2012 at 8:31

vijaykumar

4,8367 gold badges40 silver badges56 bronze badges

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