Cannot bind JSON to ASP.NET Model in multi part post

Question

I am using ASP.NET MVC3 controller to receive multi-part form post from WP7 app. The format of the post is something as follows:

    {User Agent stuff}
    Content-Type: multipart/form-data; boundary=8cdb3c15d07d36a

    --8cdb3c15d07d36a
    Content-Disposition: form-data; name="user"
    Content-Type: application/json

    {"UserName":"ashish","Password":"ashish"}

    --8cdb3c15d07d36a--

And my controller looks like:

    public class User
    {
        public string UserName { get; set;}
        public string Password { get; set; }
    }

    [HttpPost]
    public JsonResult CreateFeed(User user)
    {
    }

What I am seeing is that User is not bound to json and user object is always null. I tried making user string and manually bound it to User class using DataContractJsonSerializer and it does create and assign an object but I am baffled as to why it does not work.

I tried using non-multi-form post and found it works with the same json. Any help would be appreciated.

I saw these posts: ASP.NET MVC. How to create Action method that accepts and multipart/form-data and HTTP spec http://www.w3.org/TR/html401/interact/forms.html#h-17.13.4.2 while coming up with my code.

untested, off-the-cuff answer: change name="feedItem" to name="user" ? — bhamlin
– bhamlin, Commented Apr 13, 2012 at 16:28
Don't you need a top-level "user" element? You do with DataContractJsonSerializer generally, but not sure what's happening here. What I mean is { "user" : { "UserName" ... } } — krisragh MSFT
– krisragh MSFT, Commented Apr 26, 2012 at 20:03

Community · Accepted Answer · 2017-05-23 11:52:17Z

1

The answer you're looking for is here

You have to read it in as a string and parse that internally. So your action would look like this:

[HttpPost]
public JsonResult CreateFeed(string jsonResponse)
{
    JavaScriptSerializer jsonSerializer = new JavaScriptSerializer();
    User user = jsonSerializer.Deserialize<User>(jsonResponse);
}

Or if you don't have nice helpful Content-Disposition with names to associate with the controller action methods you can do something like the below:

[HttpPost]
public JsonResult CreateFeed()
{
    StreamReader reader = new StreamReader(Request.InputStream);
    string jsonResponse = reader.ReadToEnd();

    JavaScriptSerializer jsonSerializer = new JavaScriptSerializer();
    User user = jsonSerializer.Deserialize<User>(jsonResponse);
}

This approach is further outlined here

edited May 23, 2017 at 11:52

CommunityBot

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answered Oct 24, 2013 at 11:53

Eoin

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