Vim function to call bash script with argument and return result

Question

I have a bash script which takes a single argument and returns around 8-10 lines of text.

I'd like to be able to call this script from within vim. Ideally by highlighting a string of characters as the argument. I'd then like the output of the script to be displayed in a new pane.

I'm new to vim so I'm not sure if this can be done simply by creating a command in my vimrc file or if I need to create a plugin.

Any advice would be much appreciated.

after a bit of googling I've come up with

function! Foo(a1)
    new
    r !myscript a:a1
endfunction

This doesn't quite work yet. It seems to pass the name a:a1 rather than the value.

sehe · Accepted Answer · 2011-08-07 18:45:58Z

5

I'd start with a simple function like so (note: the sample uses echo as the script... Kinda lame... but you get the idea)

function! CallMyScript(params)
    new                 " open a new buffer
    " se buftype=nofile " add spice to taste, e.g.
    silent! exec "r!echo '" . a:params . "'"
endfunction

and then a mapping for visual mode like;

:vnoremap QQ y:call CallMyScript(@")<Enter>

This will call the script with the currently selected text when you hit QQ

answered Aug 7, 2011 at 18:45

sehe

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6 Comments

rvabdn Over a year ago

I'm a wee bit confused about the ". a:params ." say I had two arguemnts to pass to my script how would I change that?

sehe Over a year ago

I'm assuming shell quoting applies; Dropping the sinqle quotest would probably do what you what

dza Over a year ago

What if the script is a bash function or alias? It (didn't work) wasn't available for me in this way (possibly due to no bashrc being loaded), so I had to retype everything in a one-liner. Isn't there a smarter way?

sehe Over a year ago

@dezza in that case, call the right program (e.g. bash): bash -c my_alias. Be aware of shell quoting/escaping. Not for the faint of heart :) (Just make a shell script for it?)

dza Over a year ago

sehe: It actually returned "command not found" .. Are you sure the chain of sources (.bashrc and from there) are happening with "bash -c" ?

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