Getting arguments from pipe in python program

Question

I need to execute my python program in the following way: echo -e arg1|myprogram.py.

In this way if I try to get the arguemnts passed to my program I get an nothing ( print(sys.arg)). How is it possible to get the arguments like that?

What you're trying to do is to read from stdin, there are plenty of questions about that, now that you know what you're looking for ;-) Possible duplicate of Python Read from Stdin with Arguments — Jaffa
– Jaffa, Commented Nov 26, 2018 at 8:50

Crazy · Accepted Answer · 2018-11-26 08:52:54Z

2

Try that script

import sys

print(sys.argv, sys.stdin.read())

And run

echo "a" | python test.py

['test.py'] a

answered Nov 26, 2018 at 8:52

Crazy

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