Python pass in function as argument, print the function name and results [duplicate]

Question

If I want to pass a function func1 as argument in another function, but want to return the function name, what shall I do?

let say

def func1(x):
    return x**2

def main_function(func1,x):
    .....
    return ___(name of func1),value of func1(x)___

which means I want things like:

func_name, result = main_function(func1,2)

print(func_name)
func1
print(result)
4

However, note that functions can have more than one identifier, or none. The __name__ will remain the first one it was assigned to, unless otherwise updated. — jonrsharpe
– jonrsharpe, Commented Mar 23, 2018 at 8:28

Junhee Shin · Accepted Answer · 2018-03-23 08:26:50Z

3

def func1(x):
    return x**2

def main_function(f,x):
    print('f name=', f.__name__)
    print('f value=', f(x))


main_function(func1, 5)

output is

f name= func1
f value= 25

answered Mar 23, 2018 at 8:26

Junhee Shin

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Comments

Szabolcs · Accepted Answer · 2018-03-23 08:27:23Z

1

Try this:

def main_function(f, x):
    return f.__name__, f(x)

answered Mar 23, 2018 at 8:27

Szabolcs

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Matphy · Accepted Answer · 2018-03-23 08:28:00Z

1

Just use __name__ to get function name as str.

def main_function(func, x):
    # do something else
    return func.__name__, func(x)

answered Mar 23, 2018 at 8:28

Matphy

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