How to upload files with additional data in ASP.NET MVC

Question

How can i upload a file with additional data in ASP.NET MVC? This is what I have so far:

 @using (Html.BeginForm("CreateSiteLogo", "SiteSettings", FormMethod.Post))
 {
     @Html.TextBoxFor(a=>a.SiteNameKey)

     <input type="file" name="logo" id="logo" />
     <input type="submit" />
 }

Action:

[HttpPost]
public ActionResult CreateSiteLogo(SiteSettingsAPIModel siteSetting)
{
    // Handle model
}

Model:

public class SiteSettingsAPIModel
{
    public int Id { get; set; }
    public string SiteNameKey { get; set; }
    public byte[] SiteLogo { get; set; }
    public string ImageFormat { get; set; }
}

I can only get the value of the input[text] but not the input[file]. I tried using Request.Files[0] but I'm always getting null.

Have you put a break point on your ActionResult to see if the file is coming through? — Izzy
– Izzy, Commented Dec 7, 2016 at 9:23
A better approach would be to add an onchange listener to the file input, post the file through ajax and return the filename as what it has been saved. Then you could add the filename to the model — Gecko
– Gecko, Commented Dec 7, 2016 at 9:23
Specify enctype in your form like this: Html.BeginForm("CreateSiteLogo", "SiteSettings", FormMethod.Post, new { enctype = "multipart/form-data" }. Then you'll be able to access Request.Files[0] — Andre Borges
– Andre Borges, Commented Dec 7, 2016 at 9:27

vrharilal · Accepted Answer · 2016-12-07 10:38:38Z

3

If you are using file upload in View then you must specify the enctype = "multipart/form-data" in BeginForm

    @using (Html.BeginForm("CreateSiteLogo", "SiteSettings", FormMethod.Post, new { enctype = "multipart/form-data" }))
{
    @Html.TextBoxFor(a => a.SiteNameKey)

    <input type="file" name="logo" id="logo" />
        <input type="submit" />
}

and in the Controller side,

public ActionResult CreateSiteLogo(SiteSettingsAPIModel siteSetting, HttpPostedFileBase logo)
    {
        //Getting the file path
        string path = Server.MapPath(logo.FileName);

        //getting the file name
        string filename = System.IO.Path.GetFileName(logo.FileName);
        using (var binaryReader = new BinaryReader(logo.InputStream))
        {
            fileContent = binaryReader.ReadBytes(logo.ContentLength);
        }
        siteSetting.SiteLogo = fileContent;

        return View();
    }

the controller code shall be modified according to your requirement. Hope its helpful

edited Dec 7, 2016 at 10:38

answered Dec 7, 2016 at 9:41

vrharilal

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1 Comment

user3159792 Over a year ago

Thanks a lot :) However it turns out i need to change the type of the logo from byte array to http posted file base. That way i won't have to add a second parameter to my action. Again thanks :D

Bob Dust · Accepted Answer · 2016-12-07 09:41:23Z

1

This could help:

@model SandBox.Web.Models.SiteSettingsAPIModel
@using (Html.BeginForm("CreateSiteLogo", "SiteSettings", FormMethod.Post, new { enctype = "multipart/form-data" }))
{
    @Html.TextBoxFor(a => a.SiteNameKey)

    <input type="file" name="SiteLogo" id="logo" />
    <input type="submit" />
}

public class SiteSettingsAPIModel
{
    public int Id { get; set; }
    public string SiteNameKey { get; set; }
    public HttpPostedFileBase SiteLogo { get; set; }
    public string ImageFormat { get; set; }
}

answered Dec 7, 2016 at 9:41

Bob Dust

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