How to upload a file in Selenium WebDriver with no 'input' element

Question

I have a HTML page with button named "Upload" and id: btn-import-questions. The element:

<button class="btn btn-success btn-sm col-lg-11" id="btn-import-questions" data-ts-file-selector="questions-import-init">  Upload&nbsp;<i class="fa fa-upload"></i></button>

I tried a Selenium Java code like this:

driver.findElement(By.id("btn-import-questions")).sendkeys("C:/path/to/file.xlsx");

But since this is an upload button and not an input-type element, the above code is not working.

Window popup will appear immediately and asking for the file path with open and cancel button — Thirunavukarasu Paramasivam
– Thirunavukarasu Paramasivam, Commented Jul 17, 2015 at 6:28
And when you choose a file using this pop up window, will the name of this file appear somewhere on the page after the pop up disappears? — Eugene S
– Eugene S, Commented Jul 17, 2015 at 6:30
After providing the file path and click on open, suddenly the popup window disappears and the data in the file are imported to my application. — Thirunavukarasu Paramasivam
– Thirunavukarasu Paramasivam, Commented Jul 17, 2015 at 6:34
Is your window showing uploaded file path..?? Once check it directly on website. — Saritha G
– Saritha G, Commented Jul 17, 2015 at 6:46

Visko · Accepted Answer · 2018-11-15 13:53:14Z

8

Check the DOM because somewhere there must be an <input type="file">. The website's javascript will call the .click() of this element to pop up the file selector dialog and closing the dialog with a selection will provide the path. With Selenium the same can be achieved with the .sendkeys():

driver.findElement(By.xpath("//input[@type=\"file\"]")).sendkeys(localFilePath);

edited Nov 15, 2018 at 13:53

answered Nov 15, 2018 at 13:26

Visko

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Community · Accepted Answer · 2017-05-23 12:09:55Z

3

You are doing it almost correctly, except that sendKeys() should be called on the input with type="file" that is, most likely invisible in your case. If this is the case, make the element visible first:

Selenium Webdriver - click on hidden elements

edited May 23, 2017 at 12:09

CommunityBot

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answered Jul 17, 2015 at 12:16

alecxe

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Comments

Mihai Vlasceanu · Accepted Answer · 2020-04-30 09:19:17Z

This one works for me:

    String CSVFile = "C:\\D\\Projects\\file.csv";
WebElement fileElement=this.driver.findElement(By.xpath("//[text()='fileElement']"));
            this.wait.until(ExpectedConditions.elementToBeClickable(fileElement ));
            fileElement .click();

            StringSelection ss = new StringSelection(CSVFile);
            Toolkit.getDefaultToolkit().getSystemClipboard().setContents(ss, null);

            //native key strokes for CTRL, V and ENTER keys
            Robot robot = new Robot();

            robot.keyPress(KeyEvent.VK_CONTROL);
            robot.keyPress(KeyEvent.VK_V);
            robot.keyRelease(KeyEvent.VK_V);
            robot.keyRelease(KeyEvent.VK_CONTROL);
            robot.keyPress(KeyEvent.VK_ENTER);
            robot.keyRelease(KeyEvent.VK_ENTER);

shaz sanz · Accepted Answer · 2019-12-30 05:44:22Z

You can use AutoIT tool to do this. Use below code in AutoIT .Au3 file to upload.

sleep(1000)
If WinExists("[TITLE:Open]") Then

 Local $hWnd = WinWaitActive ("[TITLE:Open]", "",15)
 WinActivate($hWnd)
 ;WinWaitActive("Open", "", 10)
 ControlFocus("Open","","Edit1")
 ControlsetText("Open","","Edit1",$CmdLine[1])
 ControlClick("Open","","Button1")

ElseIf WinExists("[TITLE:File Upload]") Then

 Local $hWnd = WinWaitActive ("[TITLE:File Upload]", "",15)
 WinActivate($hWnd)
 ;WinWaitActive("Open", "", 10)
 ControlFocus("File Upload","","Edit1")
 ControlsetText("File Upload","","Edit1",$CmdLine[1])
 ControlClick("File Upload","","Button1")

Else

 Local $hWnd = WinWaitActive ("[TITLE:Choose File to Upload]", "",15)
 WinActivate($hWnd)
 ;WinWaitActive("Open", "", 10)
 ControlFocus("Choose File to Upload","","Edit1")
 ControlsetText("Choose File to Upload","","Edit1",$CmdLine[1])
 ControlClick("Choose File to Upload","","Button1")

EndIf

And then use below code in you C# code to invoke it.

String sExe=(<EXE file path>+" "+<Upload file path>);

Runtime.getRuntime().exec(sExe);
Thread.sleep(5000);

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