If variable not empty display variable without repeating variable name

Question

Hello there do you know a way for writing this in PHP without repeating the variable name?

if($abcdefg["blaBlaBlaBlaBlaBlaBlaBlaBlaBla"]!=="") {
    echo $abcdefg["blaBlaBlaBlaBlaBlaBlaBlaBlaBla"];
} else if($abcdefg["evenMoreBlaBlaBlaBlaBlaBlaBlaBlaBlaBla"]!=="") {
    echo $abcdefg["evenMoreBlaBlaBlaBlaBlaBlaBlaBlaBlaBla"];
} else if($abcdefg["stillAlotBlaBlaBlaBlaBlaBlaBlaBlaBla"]!=="") {
    echo $abcdefg["stillAlotBlaBlaBlaBlaBlaBlaBlaBlaBla"];
}

Of course you can write

$a = $abcdefg["blaBlaBlaBlaBlaBlaBlaBlaBlaBla"];
$b = $abcdefg["evenMoreBlaBlaBlaBlaBlaBlaBlaBlaBlaBla"];
$c = $abcdefg["stillAlotBlaBlaBlaBlaBlaBlaBlaBlaBla"];

if($a) { echo $a; } else if($b) { echo $b; } else if ($c) { echo $c; }

This is a bit shorter but I still wonder if there is some syntactical nice thing to write it without variable repetition.

Ternary operator does not solve the problem because of the "elseif" I think.

either spell it out in full, or copy/reference to another variable and use that. there are no "shortcuts". that or just don't use insanely long variable/key names... — Marc B
– Marc B, Commented Jun 30, 2015 at 18:04
possible duplicate of Check if variable is set and then echo it without repeating? — Jocke Med Kniven
– Jocke Med Kniven, Commented Jun 30, 2015 at 18:07
The problem with ternary is the "elseif" i guess? However i like the answers of bitworking and rizier123 both solutions are nice. — Blackbam
– Blackbam, Commented Jun 30, 2015 at 18:10

Rizier123 · Accepted Answer · 2015-06-30 18:05:49Z

4

This should work for you:

Just loop through all indexes, which you want to check and print them if they pass the if statement, e.g.

$indexes = ["blaBlaBlaBlaBlaBlaBlaBlaBlaBla", "evenMoreBlaBlaBlaBlaBlaBlaBlaBlaBlaBla", "stillAlotBlaBlaBlaBlaBlaBlaBlaBlaBla"];

foreach($indexes as $key) {
    if($abcdefg[$key] !== "") {
        echo $abcdefg[$key];
        break;
    }
}

answered Jun 30, 2015 at 18:05

Rizier123

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Comments

bitWorking · Accepted Answer · 2015-06-30 18:06:34Z

1

You can do a variable declaration in the if condition:

if(($var = $abcdefg["blaBlaBlaBlaBlaBlaBlaBlaBlaBla"]) !== "") {
    echo $var;
}

answered Jun 30, 2015 at 18:06

bitWorking

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Comments

Mat · Accepted Answer · 2015-06-30 18:29:05Z

0

What about declaring a function for the ... hmmm ... functionnality?

function echoNotEmpty($s)
{
    if ($s !== '') echo $s;
}
echoNotEmpty($abcdefg["blaBlaBlaBlaBlaBlaBlaBlaBlaBla"]);
echoNotEmpty($abcdefg["evenMoreBlaBlaBlaBlaBlaBlaBlaBlaBlaBla"]);
echoNotEmpty($abcdefg["stillAlotBlaBlaBlaBlaBlaBlaBlaBlaBla"]);

Or even shorter:

echo $abcdefg["blaBlaBlaBlaBlaBlaBlaBlaBlaBla"];
echo $abcdefg["evenMoreBlaBlaBlaBlaBlaBlaBlaBlaBlaBla"];
echo $abcdefg["stillAlotBlaBlaBlaBlaBlaBlaBlaBlaBla"];

I mean, if you don't want to echo empty string and you still echo them, who cares?

answered Jun 30, 2015 at 18:29

Mat

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1 Comment

Blackbam Over a year ago

The problem is the "elseif" (there are maybe two strings which are not empty, and only the first should be echoed).

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