php - how to echo a value if the variable is empty

Question

I know how to do something like this in Perl, but not sure how to do it the correct way in Php...

Say I have a string called: $string

What is the proper way to do this:

echo "Code is " . ($string || "Great");

So it would print $string to the browser, IF it had value, otherwise it would print "Great" to the browser.

do I have to use a if statement or is there a way to do it like this:

($string == "s1") ? 's2':'s1'

Sorry for my Php Ignorance :)

-Richard

The PHP way to do it is echo "Code is " . ($string ?: "Great"); Read about the conditional ternary operator. — axiac
– axiac, Commented Jan 30, 2016 at 22:09

Jose Luis Bernat · Accepted Answer · 2016-01-30 22:08:25Z

1

echo "Code is " . (empty($string) ? "Great" : $string);

answered Jan 30, 2016 at 22:08

Jose Luis Bernat

14911 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

that is what I was looking for. It worked. Thank you. :)

blacksheep_2011 · Accepted Answer · 2016-01-30 22:52:48Z

0

Use this to check if the string is set:

echo (isset($string) && $string !== '')? $string : "Great";

When only use empty a string which contains only '0' will be empty.

answered Jan 30, 2016 at 22:09

blacksheep_2011

1,1433 gold badges11 silver badges22 bronze badges

Overcomplicated. echo $string ?: "Great" does the job more straightforwardly.