PHP output multiple variable values if they exist

Question

I have to output a list of multiple values. These values are not part of an array. I am doing it like this:

$value_1 = get_field('value_1');
$value_2 = get_field('value_2');
$value_3 = some_other_function('value_3');
$value_4 = another_function('value_4', 'one_more_param');

echo '<ul>';

if ($value_1) :
  echo '<li>' . $value_1 . '</li>';
endif;

if ($value_2) :
  echo '<li>' . $value_3 . '</li>';
endif;

if ($value_3) :
  echo '<li>' . $value_3 . '</li>';
endif;

if ($value_4) :
  echo '<li>' . $value_4 . '</li>';
endif;

echo '</ul>';

I have about 30 values. Is there a quicker, cleaner way to output this?

security improvement : htmlentities($value_X) instead of just $value_X when you output data in HTML — Bobot
– Bobot, Commented Jul 26, 2019 at 14:06

u_mulder · Accepted Answer · 2019-07-26 14:07:25Z

2

Collect your values to array and iterate over this array:

$values = [
    get_field('value_1'),
    get_field('value_2'),
    some_other_function('value_3'),
    another_function('value_4', 'one_more_param'),
];
echo '<ul>';
foreach ($values as $value) {
    if ($value) {
        echo '<li>' . $value . '</li>';
    }
}
echo '</ul>';

answered Jul 26, 2019 at 14:07

u_mulder

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2 Comments

Andreas Over a year ago

Ha! I didn't see the if() in the loop. How did I miss that?

CyberJ Over a year ago

That is brilliant! Works perfectly.

Nigel Ren · Accepted Answer · 2019-07-26 14:23:55Z

2

Create a function to check if it needs display the item, then pass the value each time...

function displayListItem( $value ) {
    if ( $value )   {
        echo '<li>'.$value.'</li>';
    }
}
echo '<ul>';
displayListItem(get_field('value_1'));
displayListItem(get_field('value_2'));
displayListItem(some_other_function('value_3'));
displayListItem(another_function('value_4', 'one_more_param'));
echo '</ul>';

answered Jul 26, 2019 at 14:23

Nigel Ren

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