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I have two lists that I want to plot with ListLinePlot:

list1 = {1, Missing, 3, Missing, 1, 1, 1, Missing, 2, 2, Missing, 1, 2, 1, 1, 2, Missing, 3, Missing, 2, 3, 3, 4, Missing, Missing, 2, Missing, Missing, 1, 3, Missing, 1, 4, 2, 3, 10, 3, 8, 4, 10, 4, 6, 5, 3};
list2 = Range[44];
ListLinePlot[{list1, list2}]

However the plot that I produce with this code is wrong enter image description here

When I replace all Missing Values with 0 like this:

ListLinePlot[list1/. Missing -> 0, list2}]

I will get a correct plot like this: enter image description here

I just want list1 with missing values to be displayed a the correct position... But as you can see, the first and third value of list1is not displayed in the plot. Why? Many thanks in advance

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    $\begingroup$ You say that you get the "correct plot" by just replacing Missing with 0. What is wrong with that? "I just want list1 with missing values to be displayed a the correct position." I don't know what you mean by this. Can you explain more clearly what you're trying to do here? $\endgroup$ Commented Jul 9 at 18:07
  • $\begingroup$ @march: I would also like to show the data gaps (i.e. missing values). But did not think about that there could be a problem if a data point is "isolated" by Missing values which is of course a problem when plotting a Lineplot... $\endgroup$ Commented Jul 9 at 18:47

1 Answer 1

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Points that do not have any neighbors except Missing cannot be connected to anything, i.e. no line connects them. But if you add PlotMarkers -> Automatic you will see also these isolated points.

list1 = {1, Missing, 3, Missing, 1, 1, 1, Missing, 2, 2, Missing, 1, 
   2, 1, 1, 2, Missing, 3, Missing, 2, 3, 3, 4, Missing, Missing, 2, 
   Missing, Missing, 1, 3, Missing, 1, 4, 2, 3, 10, 3, 8, 4, 10, 4, 6,
    5, 3};
list2 = Range[44];
ListLinePlot[{list1}, PlotMarkers -> Automatic]

enter image description here

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  • $\begingroup$ Many thanks, could have tried that before I asked... $\endgroup$ Commented Jul 9 at 18:44

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