parsing data with regex in C#

Question

I have string: text and something and something like f213 @@ -1,9 +1,11 @@ etc etc and litle more etc etc

i woul dlike to get now @@ -1,9 +1,11 @@. Numbers are not fixed and can be changed...

My regex which not working:

(@@ -)([0-9]+)(,)([0-9]+)( +)([0-9]+)(,)([0-9]+)( @@)

Can someone see error in my regex?

They don't make the regex wrong, but you also don't need any of your round brackets, unless you want to capture e.g. the numbers themselves. @@ -[0-9]+,[0-9]+ \+[0-9]+,[0-9]+ @@ — anton.burger
– anton.burger, Commented Mar 27, 2012 at 14:13
How about an actual snipet of data and not saying etc, etc,etc. Provide all different combinations. -1 — ΩmegaMan
– ΩmegaMan, Commented Mar 27, 2012 at 14:18
@OmegaMan you mean you can't tell from the regex the OP provided what's being asked? Downvote's a bit harsh... — anton.burger
– anton.burger, Commented Mar 27, 2012 at 14:22

aquinas · Accepted Answer · 2012-03-27 14:09:04Z

3

You need to escape your plus:

(@@ -)([0-9]+)(,)([0-9]+)( \+)([0-9]+)(,)([0-9]+)( @@)

By the way, this is the best tool ever: http://www.nregex.com/nregex/default.aspx when trying to see what a regex is doing.

answered Mar 27, 2012 at 14:09

aquinas

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Cokoyan · Accepted Answer · 2012-03-27 15:22:08Z

1

Maybe an other solution :

Regex.IsMatch(yourString, @"@@\s(.+?)\s(.+?)\s@@", RegexOptions.Singleline);

With your exemple, the group 1 will be "-1,9" and the group 2 "+1,11".

answered Mar 27, 2012 at 15:22

Cokoyan

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heijp06 · Accepted Answer · 2012-03-27 14:15:52Z

0

Have you considered using String.Split()?

string input = "f213 @@ -1,9 +1,11 @@";
string[] fields = input.Split(new[] { "@@" }, StringSplitOptions.None);
string result = "@@" + fields[1] + "@@";

answered Mar 27, 2012 at 14:15

heijp06

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