I need to make a loop that checks if an array ( $array ), contains a string ( 'thisisaverylongstring' ), that contains another string ( 'isavery' ).
How would I write this in valid PHP?
4 Answers
If it is a simple as you say it is, you can use stripos (case insensitive string search):
foreach ($array as $element) {
if (stripos($element, 'isavery') !== false) {
echo 'Found it!';
break;
}
}
Comments
I don't know what's your actual requirement is but as from my understanding the following function could work
function checkInArray($array, $val)
{
if(in_array($val,$array))
return true;
}
function checkvalinarray($array2D, $val1, $val2)
{
foreach($array2D as $array1D)
{
if(checkInArray($array1D,$val2))
return true;
}
}
Comments
$arrayData = array('This is a very long string',
'This is a short string',
);
$needle = 'very';
$matches = array_filter( $arrayData,
function($data) use ($needle) {
return (stripos($data,$needle) !== FALSE);
}
);
if (count($matches) > 0) {
echo 'Match found';
}
var_dump($matches);
Comments
$stringToLookFor = 'isavery';
$inArray = FALSE; //does the string exist in the array?
foreach($array as $string)
{
if(strpos($string, $strongToLookFor) !== FALSE)
{
$inArray = TRUE;
}
}
if($inArray)
{
echo 'String "' . $stringToLookFor . '" found in array';
}
answered Mar 19, 2012 at 17:03
Richard Parnaby-King
15k11 gold badges75 silver badges131 bronze badges
in_array()andarray_search()functions ?'thisisaverylongstring'will contain'isavery'. So why don't you look for the short one only?