I have array of chars:
char macChars=[12];
The content of it is e.g. macChars[0]=53, macChars[1]=66 ... I need to convert these numbers to hex chars, so i would have another array:
macCharsHex[0]=5 //value 53 in hex
macCharsHex[1]=B //value 66 in hex
Thank you.
Assuming ASCII, your example already does contain the values you want them to contain. So you don't have to convert anything. Maybe you want to print them?
This should work:
char hex[255] = {0}; // Varible to hold the hex value
int dec = 1234; // Decimal number to be converted
sprintf(hex,"%X", dec);
printf("%s", hex); // Print hex value
Use sprintf(), for instance. Note that it will take more space, if you have 12 bytes you will need 24 + 1 bytes for the string representation, since each byte requires two characters in hex and then the terminating '\0'-byte.
I suspect that I don't understand the question at all, especially not the example given.
If you have macChars[0] == 53, which is 0x35 in hex, then I would expect to get maxCharsHex[0] == '3' and macCharsHex[1] == '5' after the first char has been converted. This is done like so with sprintf():
sprintf(maxCharsHex, "%02x", (int) macChars[0] & 0xff);
The cast and mask is to be on the safe side for signed characters.
They are already converted, since character in C are represented by their corresponding character codes.
Therefore, as far as storing things in arrays is concerned there is nothing you need to do and if you want "5" and "B" to show up correctly when printing or doing something like that its a matter of using the correct printing function (putchar, printf with %c, etc).
arr[0] = 'B';?