How to catch "OpenCV Error" in Python

Question

If I get OpenCV Error: ...

what's the syntax to catch it since OpenCV Error uses two words? I'm able to catch the following cv.error but how would I catch this?

EDIT:

I don't get it... is the answer obvious? Am I being unclear?

EDIT 2

I can't reproduce it b/c I'm on a different computer but it looked similar to:

OpenCV Error: Bad argument. Something something array

cv.error: This is another error

I'm able to catch cv.error but not OpenCV Error with the following:

try:
    # do a thing
except (cv.error, OpenCV Error):
    print "Can't do the thing"
    sys.exit(1)

What is the exception raised when you run into this OpenCV Error? — Makoto
– Makoto, Commented Jan 15, 2012 at 22:44
Yes, you're being very unclear. Please explain your problem more clearly. Unfortunately I can't tell you specifically what you should improve in your question, because I don't understand it at all. — Petr Viktorin
– Petr Viktorin, Commented Jan 15, 2012 at 22:47
Some OpenCV functions don't throw errors, they print out a message and exit the program (either with exit or abort, I can't remember). In other words, there are some errors that can't be caught. — Chris Eberle
– Chris Eberle, Commented Jan 16, 2012 at 0:50

mathematical.coffee · Accepted Answer · 2012-01-16 00:00:45Z

43

Try cv2.error.

try:
    ...
except cv2.error as e:
    ...

Here's the page from the documentation but it's only for the C/C++ interface -- I can't find anything on the Python error handling for OpenCV (I find the documentation for the Python interface to be sadly lacking).

answered Jan 16, 2012 at 0:00

mathematical.coffee

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milahu · Accepted Answer · 2020-07-11 15:39:25Z

6

you can easily inspect the error object, like

fvs = imutils.video.FileVideoStream(args.input).start()

while fvs.more():

  frame = fvs.read()

  try:
    
    grayframe = cv2.cvtColor(frame, cv2.COLOR_BGR2GRAY)

  except cv2.error as e:
    
    # inspect error object
    print(e)
    for k in dir(e):
      if k[0:2] != "__":
        print("e.%s = %s" % (k, getattr(e, k)))

    # handle error: empty frame
    if e.err == "!_src.empty()":
      break # break the while loop

answered Jul 11, 2020 at 15:39

milahu

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