i am not much familiar with regex expressions use in Java.
If i have a String this/is/a/file!/path
now with substring and indexOf i can find the name file appearing inbetween / and ! but i am pretty sure such tasks must be much easier using regexes.
Can someone give me an example for doing so using regex expressions?
Another way is to use Pattern and Matcher. Here you can use groups and more complex operations
Pattern pattern = Pattern.compile(yourRegex);
Matcher matcher = pattern.matcher(yourText);
while(matcher.find()) {
System.out.println(matcher.group(1));
}
Take a look at
Matcher : http://docs.oracle.com/javase/1.5.0/docs/api/java/util/regex/Matcher.html
Pattern : http://docs.oracle.com/javase/1.4.2/docs/api/java/util/regex/Pattern.html
Regex in Java : http://docs.oracle.com/javase/tutorial/essential/regex/
somthing as .*/([^!]*)!.* should do this... then you can use a matcher to find the 1st group (the part between parenthesis, the 0th group is the whole match)
I didn't test this solution...
You can create a Pattern Object with a regular expression and then create a matcher object from it to parse your String.
String regex = ".*/(.*)!";
Pattern p = Pattern.compile (regex);
Matcher m = p.matcher(StringToBeMatched);
if (m.find()) {
String filename = m.group (1);
}
The simplest way of using them in Java is by using the String.matches method:
boolean matches = "abc".matches("[a-z]+");
That would yield true.
The second way of doing it is useful if you have to use a specific regex pattern a lot of times. You can compile it and reuse it:
Pattern pattern = Pattern.compile("[a-z]+");
Matcher matcher = pattern.matcher("abc");
boolean matches = matcher.matches();
filepart of the string.