How to do floating point computation in python ?
for j in range(10 , 50):
print "(10/(j+1)) is %f " % (10/(j+1))
Why is the output all 0s ?
j must be an integer , but I need the floating result .
thanks
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2 Answers
In Python2, / will truncate the quotient of two integers into an integer,
you can either do
for j in range(10 , 50):
print "(10/(j+1)) is %f " % (10.0/(j+1))
or not to truncate globally, just as Python3 does
from __future__ import division
for j in range(10 , 50):
print "(10/(j+1)) is %f " % (10/(j+1))
Comments
try 10.0 instead of 10. python is interpreting the 10 as an integer type and the division as a result is integer division. You could also cast 10 or (j + 1) to a double type manually but 10.0 seems the easiest to me.
