My English issnt so good sorry for that.
i have a array:
Array ( [name] => Array
(
[0] => Sorry the name is missing!
[1] => Sorry the name is to short!
)
)
Now I want to test with in_array for eg "name".
if (in_array("name", $false["name"])) {
echo "the array keys";
}
but it dsnt work. could annybody help me please? thanks a lot.
Try array_key_exists(): link
if(array_key_exists('name', $false['name'])) {
echo $false['name'][0]; // or [1] .. or whatever you want to echo
}
in_array() does not work with multi-dimensional arrays, so it is not possible to use in_array() here. When you are searching "name" in in_array() it searches in the first array and finds a key of the array named "name".
Better to use array_key_exists function. An example is given below: (remember it is only a suggestion. code may vary)
if(array_key_exists('name', $false['name'])) {
echo $false['name'][0]; // or [1] .. or whatever you want to echo
}
//$false['name'] array contains your searched data in different keys; 0,1,2,....
You can use foreach() to loop the first array then search using in_array() but that will not be a good method because it will take more time to find.
Best of luck :)
Maybe you need to walk through the array first, then check it
function in_multiarray($str, $array)
{
$exists = false;
if (is_array($array)) {
foreach ($array as $arr):
$exists = in_multiarray($str, $arr);
endforeach;
} else {
echo $array . ' = ' . $str . "\n";
if (strpos($array, $str) !== false) $exists = true;
}
return $exists;
}
in_array() looks for the exact value. So you would need to specify "Sorry the name is missing!" instead of just "name".
For example:
if (in_array("Sorry the name is missing!", $false["name"])) {
echo "the array keys";
}
Where:
$false = array( 'name' => array(
0 => 'Sorry the name is missing!',
1 => 'Sorry the name is to short!'),
);
If you are searching for array key name in your main array:
$arr = array( "name" => array(
"0" => "Sorry the name is missing!",
"1" => "Sorry the name is to short!"
));
if(array_key_exists('name', $arr)) {
print_r( $arr['name'] );
} else {
echo "array key not found";
}
It will not find name if you will search in $arr['name'] because it contains only 0 and 1 array keys at this level.
If you are wanting to use in_array you just need to put the second parameter as the array you have defined example
if(in_array('name',$false){
//do your stuff
print_r($false['name']); //this will print the array of name inclusive of [0] and [1]
}
There are more example given in the in_array php manual. please check it out.
