PHP Extract numbers from a string

Question

I want to extract numbers from a string in PHP like following :

if the string = 'make1to6' i would like to extract the numeric character before and after the 'to' substring in the entire string. i.e. 1 and 6 are to be extracted

i will be using these returned values for some calculations.' i would like to extract the numeric character before and after the 'to' substring in the entire string. i.e. 1 and 6 are to be extracted

The length of the string is not fixed and can be a max of 10 characters in length.The number can be of max two digits on either side of 'to' in the string.

Some example string values :

sure1to3
ic3to9ltd
anna1to6
joy1to4val
make6to12
ext12to36

thinking of something like :

function beforeTo(string) {

    return numeric_value_before_'to'_in_the_string;

}


function afterTo(string) {

    return numeric_value_after_'to'_in_the_string;

}

i will be using these returned values for some calculations.

Have you tried looping through each character and checking if it is_int()? (php.net/is_int) — Bailey Parker
– Bailey Parker, Commented Dec 3, 2011 at 19:54
I am confused. Is this task about text extraction, text validation, or both? — mickmackusa
– mickmackusa ♦, Commented Aug 9, 2022 at 11:02

Cyclonecode · Accepted Answer · 2021-09-07 10:51:44Z

2

You could use preg_match_all to achive this:

function getNumbersFromString($str) {
    $matches = array();
    preg_match_all('/([0-9]+)/', $str, $matches);
    return $matches;
}
$matches = getNumbersFromString('hej 12jippi77');

edited Sep 7, 2021 at 10:51

answered Dec 3, 2011 at 19:59

Cyclonecode

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1 Comment

mickmackusa Over a year ago

This entire pattern could be simplified to /\d+/. The capture group is unnecessary and [0-9] is more briefly expresses as \d.

Mac_Cain13 · Accepted Answer · 2011-12-05 15:05:35Z

1

Use preg_match with a regex that will extract the numbers for you. Something like this should do the trick for you:

$matches = null;
$returnValue = preg_match('/([\d+])to([\d+])/uis', 'ic3to9ltd', $matches);

After this $matches will look like:

array (
  0 => '3to9',
  1 => '3',
  2 => '9',
);

You should read somewhat on regular expressions, it's not hard to do stuff like this if you know how they work. Will make your life easier. ;-)

edited Dec 5, 2011 at 15:05

answered Dec 3, 2011 at 19:57

Mac_Cain13

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3 Comments

Sandy505 Over a year ago

tested with a string with two digits.... not working with two digits like "m6to12" but works for "m1to6"

Seldaek Over a year ago

The reason it fails with more than one digit is that it uses [\\d+] which really means one character of 0-9 or +, so it would also match a + which is really wrong. Simply writing \d+ would match 1 or more characters of 0-9, which would be better.

mickmackusa Over a year ago

Wrapping \d in a character class is pointless. The askers input does not suggest that case insensitive or multibyte matching is required. The s modifier is pointless since there is no . in the pattern. This answer is teaching plenty of bad pattern crafting practices.

Seldaek · Accepted Answer · 2011-12-03 19:56:56Z

0

You can use a regular expression as such, it should match exactly your specification:

$string = 'make6to12';
preg_match('{^.*?(?P<before>\d{1,2})to(?P<after>\d{1,2})}m', $string, $match);
echo $match['before'].', '.$match['after']; // 6, 12

answered Dec 3, 2011 at 19:56

Seldaek

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Comments

rabusmar · Accepted Answer · 2011-12-03 19:54:35Z

0

You can use this:

// $str holds the string in question
if (preg_match('/(\d+)to(\d+)/', $str, $matches)) {
    $number1 = $matches[1];
    $number2 = $matches[2];
}

answered Dec 3, 2011 at 19:54

rabusmar

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2 Comments

Seldaek Over a year ago

This works, but does not validate that there is only 1 or 2 digits before/after "to", see my answer below for a more strict approach.

Sandy505 Over a year ago

@rabusmar - this works great... except it doesnt validate that the digits length should be either 1 or 2.... anyway thanks

moteutsch · Accepted Answer · 2011-12-03 19:55:22Z

0

You can use regular expressions.

$string = 'make1to6';
if (preg_match('/(\d{1,10})to(\d{1,10})/', $string, $matches)) {
    $number1 = (int) $matches[1];
    $number2 = (int) $matches[2];
} else {
    // Not found...
}

answered Dec 3, 2011 at 19:55

moteutsch

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Comments

You Qi · Accepted Answer · 2011-12-03 19:55:35Z

0

<?php

$data = <<<EOF

sure1to3
ic3to9ltd
anna1to6
joy1to4val
make6to12
ext12to36

EOF;

preg_match_all('@(\d+)to(\d+)@s', $data, $matches);
header('Content-Type: text/plain');

//print_r($matches);
foreach($matches as $match)
{
    echo sprintf("%d, %d\n", $match[1], $match[2]);
}

?>

answered Dec 3, 2011 at 19:55

You Qi

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1 Comment

mickmackusa Over a year ago

The s pattern modifier is useless because there is no . in the pattern

Ian · Accepted Answer · 2011-12-03 19:55:40Z

0

This is what Regular Expressions are for - you can match multiple instances of very specific patterns and have them returned to you in an array. It's pretty awesome, truth be told :)

Take a look here for how to use the built in regular expression methods in php : LINK

And here is a fantastic tool for testing regular expressions: LINK

answered Dec 3, 2011 at 19:55

Ian

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1 Comment

mickmackusa Over a year ago

There isn't much substance in this answer. It could have been a comment under the question.

Bailey Parker · Accepted Answer · 2011-12-03 20:03:31Z

0

<?php
list($before, $after) = explode('to', 'sure1to3');

$before_to = extract_ints($before);
$after_to  = extract_ints($after);

function extract_ints($string) {
    $ints = array();
    $len = strlen($string);

    for($i=0; $i < $len; $i++) {
        $char = $string{$i};
        if(is_numeric($char)) {
            $ints[] = intval($char);
        }
    }

    return $ints;
}
?>

A regex seems really unnecessary here since all you are doing is checking is_numeric() against a bunch of characters.

answered Dec 3, 2011 at 20:03

Bailey Parker

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1 Comment

mickmackusa Over a year ago

It seems entitely possible, to me, that to could occur more than once in the string.

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