PHP date format error

Question

I have an array with a key timestamp with the following content

"timestamp" => "2011-11-29 00:00:00"

When i try to change the format using this

date("F j, Y", $data['Visitor']['timestamp']);

i get the following error

A non well formed numeric value encountered

Shakti Singh · Accepted Answer · 2011-11-30 10:01:26Z

6

You should be using the strtotime on the datetime data to convert it into Unix timestamp first.

date("F j, Y", strtotime($data['Visitor']['timestamp']));

Checkout the documentation of date it accept a Unix timestamp as a second parameter and you are passing a datetime value.

DEMO

answered Nov 30, 2011 at 10:01

Shakti Singh

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Wesley van Opdorp · Accepted Answer · 2011-11-30 10:02:57Z

1

The function requires the Unix Time which is numeric - and not a string formatted date.

As @Shakti Singh mentions you should use strtotime for that.

From the PHP docs on the timestamp parameter:

The optional timestamp parameter is an integer Unix timestamp that defaults to the current local time if a timestamp is not given. In other words, it defaults to the value of time().

answered Nov 30, 2011 at 10:02

Wesley van Opdorp

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John Conde · Accepted Answer · 2013-01-29 03:20:40Z

0

A newer way to do this as of PHP 5.2 is the DateTime class:

$datetime = new DateTime('2011-11-29 00:00:00');
echo $datetime->format('F j, Y');

See it in action

answered Jan 29, 2013 at 3:20

John Conde

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