Java regex split

Question

I'm new to regex.

I have a string 2¯< .

I want to get the '&#number' part.

I tried with the following pattern:

Pattern.compile("\\&#([0-9]+);/")

but no result.

ruakh · Accepted Answer · 2011-11-29 03:25:32Z

3

Remove the / at the end. Also, you don't need to escape the &; that character doesn't have any special meaning there. So, just:

Pattern.compile("&#([0-9]+);");

answered Nov 29, 2011 at 3:25

ruakh

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Comments

Paul Jowett · Accepted Answer · 2011-11-29 03:37:57Z

1

For completeness using ruakh's regex:

    Pattern p = Pattern.compile("&#([0-9]+);");
    Matcher m = p.matcher(s);
    while(m.find()) {
        System.out.println(m.group());
    }

answered Nov 29, 2011 at 3:37

Paul Jowett

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