Initialize linked list with linux/list.h

Question

I am using linux/list.h to work with lists, but I am having trouble getting started.

I having been experimenting with different combinations based on a few guides' recommendations, but nothing has been working so far. Here's what I believe to be my closest attempt at initialization:

typedef struct {
    int to;
    struct list_head list;
    int from;
} myFrame;

int main() {
    LIST_HEAD(listInstance);

    myFrame* foo = malloc(sizeof(*foo));
    list_add(&foo->list, &listInstance);
}

This produces the warning

initializer element is not computable at load time

at LIST_HEAD()

However, this seems to indicate that I can.

Alternatively, lists can be initialized at compile time

Would someone mind helping me wrap my brain around this?

Bill Lynch · Accepted Answer · 2011-11-23 03:36:10Z

4

You actually want to do:

LIST_HEAD(this_is_a_list_instance);

You can then do:

struct myList *foo = malloc(sizeof(*foo));
foo->to = 3;
foo->from = 4;
list_add(&foo->list, &this_is_a_list_instance);

This would also probably be more consistent if you named it myObject instead of myList.

edited Nov 23, 2011 at 3:36

answered Nov 23, 2011 at 3:14

Bill Lynch

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4 Comments

Jojo Jonas Over a year ago

So in this case, foo represents a single object in the list? And what sort of parameters will LIST_HEAD() take? I'm not sure what you mean by "this_is_a_list_instance"

Bill Lynch Over a year ago

so LIST_HEAD(this_is_a_list_list_instance) is a macro that is going to get converted into struct list_head this_is_a_list_instance = .... So I'm using that as a name for an object.

Jojo Jonas Over a year ago

Understood. Thanks for sticking with me. I have updated my question at the top.

Jojo Jonas Over a year ago

Fixed by moving LIST_HEAD() outside of main(). Haha, oh well

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