Extracting data from String using Java Regex

Question

I have a string " 11:45 AM, 12:30 PM, 04:50 PM "

I wish to extract the first time from this string using java regex.

I have created a java regex like :

"\d*\S\d*\s(AM|PM)" for this.

However i can only match this pattern in Java rather than extract it. How can i extract the first token using the Regex i created

AlexR · Accepted Answer · 2011-11-20 15:37:05Z

5

The capturing parentheses where missing. Here is the code sample that should help you.

Pattern p = Pattern.compile("(\d*):(\d*)\s(AM|PM)");
Matcher m = p.matcher(str);
if (m.find()) {
    String hours = m.group(1);
    String minutes = m.group(2);
}

answered Nov 20, 2011 at 15:37

AlexR

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1 Comment

typedefcoder2 Over a year ago

Rewritten as : Pattern p= Pattern.compile("(\\d*):(\\d*)\\s(AM|PM)"); Matcher m = p.matcher(ShowTime[i]); if(m.find()) { String hours = m.group(1); String minutes = m.group(2); String timeFormat = m.group(3); String finalTime= hours+":"+minutes+" "+timeFormat; }

Francisco Paulo · Accepted Answer · 2011-11-20 15:45:33Z

2

If you only want to extract the first time, you can use the parse method of SimpleDateFormat directly, like this:

    String testString = " 11:45 AM, 12:30 PM, 04:50 PM ";

    SimpleDateFormat sdf = new SimpleDateFormat("hh:mm aa");
    Date parsedDate = sdf.parse(testString);

    System.out.println(parsedDate);

From the api, the partse method: "Parses text from the beginning of the given string to produce a date", so it will ignore the other two dates.

Regarding the pattern:

hh --> hours in am/pm (1-12)
mm --> minutes
aa --> AM/PM marker

Hope this helps!

answered Nov 20, 2011 at 15:45

Francisco Paulo

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2 Comments

typedefcoder2 Over a year ago

Sorry could not try your solution. Thanks for Helping

Francisco Paulo Over a year ago

Don't worry about that, maybe you'll get to use it in the future :)

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