File-1:
<?php
<div>
<p>
something...
</p>
</div>
?>
File-2:
<?php
$file1= What should I write to get output of File1?
?>
I need to get html output to the $file1 variable; Please help.
-
3Your first file would not run for sure... Please clarify: is your File-1 a PHP file that you want to execute and grab its output, or is it an HTML file that you just want to read?kapa– kapa2011-11-16 10:50:45 +00:00Commented Nov 16, 2011 at 10:50
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5 Answers
I think this will work for you:
function read($file) {
ob_start();
include($file);
$content = ob_get_contents();
ob_end_clean();
return $content;
}
Use it like this:
$file = 'path/to/your/file.php';
$content = read($file);
To pass variables you can modify function above like this:
function read($file, $vars) {
ob_start();
extract($vars, EXTR_SKIP);
include($file);
$content = ob_get_contents();
ob_end_clean();
return $content;
}
$file = 'path/to/your/file.php';
$vars = array(
'var1' => 'value',
);
$content = read($file, $vars);
You can access variables in included file like this: print $var1;
you can use
http://www.php.net/manual/en/function.ob-start.php
to start output buffering, then include your file and use
http://www.php.net/manual/en/function.ob-get-contents.php
to read what was the output and finish with
http://www.php.net/manual/en/function.ob-end-clean.php
to end the buffering.
Comments
Maybe is this you are looking for:
http://www.tizag.com/phpT/fileread.php
Visit the section: PHP - File Read: fread Function
Comments
You could either set the variable in File-1 and include it:
include() / include_once() / require() / require_once()
Or you could print the contents of File-1 and use output buffering:
Comments
Use this code:
$content = file_get_contents('somefile.txt');
2 Comments
Flo
but he has php in that file, what he wants is the output of that file and not the file content itself.
Flakron Bytyqi
he can call it through url e.g file_get_contents('localhost/file1.php'), in this way he can get the html content.