Assuming whe have 8 instances of a class and 8 arrays outside the class. Something like:
float[] t1,t2,t3,t4,t5,t6,t7,t8;
public void myclass{
How can we access the array fields from inside the class? So that the first instance of the class corresponds to the first array "t1" the second to "t2" etc.
}
for (int i = 0; i < 8; i++) {
classID[i] = new myclass(i);
}
in Java, if it is out side of class it should be in other class, so you need object of that class to access that array
class Foo{
private int arr[];
public int[] getArr(){
return this.arr;
}
}
//from other class now
new Foo().getArr();
or else it needs to be static
class Foo{
public static int arr[];
}
//from other class
int arr[] = Foo.arr;
Each instance of class should contain one array. The array can be passed in the constructor, like this:
class MyClass {
private float[] t;
public MyClass(float[] aT) {
t = aT;
}
}
Then, when you create your instances, pass appropriate arrays to constructor calls:
MyClass myClass1 = new MyClass(t1);
MyClass myClass2 = new MyClass(t2);
...
Do you mean?
MyClass[] arrays = new MyClass[8];
for(int i=0;i<arrays.length;i++) arrays[i] = new MyClass();
class MyClass {
final double[] values = new double[10];
}
There is no 'outside the class' in java So
what i get u.. is u have a class in which there is 8 Float type Array u made 8 different instance of your class ..
And through each Object u want to access a different Object because "sequence of object is depend on sequence in which they are instantiated "
So for that :-
U can make a int counter as static and every time in the constructor of class u increment the counter and store that value . And access Array of respected value of counter..
You will need to declare an ArrayList of float arrays like
ArrayList<float[]> arrayList = new ArrayList<float[]>;
Then add each of your arrays to the arrayList. Each class will access arrayList.get(i).
float[]. I would usedouble[]unless you have a very good reason.