Pass a PHP array to a function?

Question

I have the following code:

$params = array(
    'api_user'  => $user,
    'api_key'   => $pass,
    'to'        => '[email protected]',
    'subject'   => 'testing from curl',
    'html'      => 'testing body',
    'text'      => 'testing body',
    'from'      => '[email protected]'
);  

/* Put the below into a function */
$request =  'api url goes here';
$session = curl_init($request);
curl_setopt ($session, CURLOPT_POST, true);
curl_setopt ($session, CURLOPT_POSTFIELDS, $params);
curl_setopt($session, CURLOPT_HEADER, false);
curl_setopt($session, CURLOPT_RETURNTRANSFER, true);
$response = curl_exec($session);
curl_close($session);
print_r($response);
/* Put the above into a function */

Basically I want to put the above code between the comments into a function, so that I can set the params and then do the following:

sendthat($params);

This is to simply clean up my page, and have the curl request grabbing the array via a function.

How can I pass the array to a function?

your code already passes an array to a function (second curl_setopt call). — Mat
– Mat, Commented Nov 7, 2011 at 14:20

Brad · Accepted Answer · 2011-11-07 14:15:03Z

5

function whatever ($params) {

    $request =  'api url goes here';
    $session = curl_init($request);
    curl_setopt ($session, CURLOPT_POST, true);
    curl_setopt ($session, CURLOPT_POSTFIELDS, $params);
    curl_setopt($session, CURLOPT_HEADER, false);
    curl_setopt($session, CURLOPT_RETURNTRANSFER, true);
    $response = curl_exec($session);
    curl_close($session);
    print_r($response);
}

$params = array(
    'api_user'  => $user,
    'api_key'   => $pass,
    'to'        => '[email protected]',
    'subject'   => 'testing from curl',
    'html'      => 'testing body',
    'text'      => 'testing body',
    'from'      => '[email protected]'
);



whatever($params);

An array assigned to a variable is no different than any other type of value assigned to a variable.

answered Nov 7, 2011 at 14:15

Brad

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1 Comment

Latox Over a year ago

Thanks, the only non sarcastic reply.

genesis · Accepted Answer · 2011-11-07 14:15:11Z

1

function_name($params);

and in function

extract($params);

(do it only when you're sure you know what you're doing)

answered Nov 7, 2011 at 14:15

genesis

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