Consteval error: taking address of an immediate function

I was solving https://projecteuler.net/problem=206, and wanted a compile time (consteval) solution.

My idea was to check every number, until the answer is found. However, my code does not compile.

Here is my code:

#include <algorithm>
#include <cstdlib>
#include <print>
#include <ranges>

using namespace std;

consteval auto check_if_square_has_special_form(int x) -> bool
{
    long long square = 1LL * x * x;

    for (const int digit : {0, 9, 8, 7, 6, 5, 4, 3, 2, 1})
    {
        const bool last_digit_is_correct = (square % 10) == digit;
        
        if (!last_digit_is_correct)
        {
            return false;
        }
        
        square /= 100;
    }

    return true;
}

auto concealed_square() -> int
{
    const auto positive_numbers = views::iota(1); // Goes on to infinity.
    const int answer = *ranges::find_if(positive_numbers, check_if_square_has_special_form);

    return answer;
}

auto main() -> int
{
    println("The answer is {}", concealed_square());

    return EXIT_SUCCESS;
}

This fails to compile, and outputs:
error: taking address of an immediate function 'consteval bool check_if_square_has_special_form(int)'.

Why do I get this error, and how to circumvent it? Using a regular for loop also doesn't seem to work.