Objective-C loop through array

Question

I have code similar to this

if (count == 0)
{
    [array1 addObject:@"No Items"];
} 
else
{
    int x;
    for (x = 0;x <= count; x++) 
    {
            [array1 addObject:[itemsArray objectAtIndex:x];
            NSLog(@"%@",array1);
    }
}

itemsArray has numbers in it (0-40). My expected result is:

1
2
3
...

However it actually does:

1
1,2
1,2,3
1,2,3,4
1,2,3,4,5
...

Why does this happen? If possible, I'd also like to ask for an example to use fast enumeration for this situation (if it suits for this).

Thanks in advance.

well it might be because you give the NSLog The full array, NSLog(@"%@",[array1 objectAtIndex:x]); or something like that — Radu
– Radu, Commented Oct 21, 2011 at 8:24
It seems like you could be using addObjectsFromArray: instead if looping through itemsArray. — 0xced
– 0xced, Commented Oct 21, 2011 at 12:25

Matt Fellows · Accepted Answer · 2011-10-21 08:21:40Z

21

You are NSLoging the whole array, not the current index of array1. What you are seeing logged is what you've coded - to log what you are expecting, change NSLog(@"%@",array1); to NSLog(@"%@",[array1 objectAtIndex:x]);

To confirm add the following after your assignment loop:

for (NSObject* o in array1)
{
    NSLog(@"%@",o);
}

answered Oct 21, 2011 at 8:21

Matt Fellows

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1 Comment

provdr Over a year ago

Cool! It did worked, indeed I didn't know how to use NSLog properly. I thought fast enumeration could be used substitution for for loops, is it only for logging?

Parag Bafna · Accepted Answer · 2011-10-21 08:31:26Z

3

Use NSLog(@"%@", [array1 objectATIndex:x]);

if (count == 0)
{
    [array1 addObject:@"No Items"];
} 
else
{
    int x;
    for (x = 0;x <= count; x++) 
    {
            [array1 addObject:[itemsArray objectAtIndex:x];
            NSLog(@"%@", [array1 objectATIndex:x]);
    }
}

answered Oct 21, 2011 at 8:31

Parag Bafna

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