link is : info.php?Submit=#img.png
so
<?php echo $_GET["Submit"]; ?>
but this wil show : #img.png
how to remove the "#" from the name so it shows : img.png ??
thanks
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substr() nz.php.net/manual/en/function.substr.phpuser557846– user5578462011-10-19 03:27:44 +00:00Commented Oct 19, 2011 at 3:27
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3 Answers
$_GET["Submit"] will not contain that, since # marks the beginning of the 'fragment', which does not get passed to the server.
If the link is info.php?Submit=%23img.png, then you can trim it like this:
<?php echo substr($_GET["Submit"], 1); ?>
Comments
Well, you could always modify the sender code to exclude the leading # (or %23 as @Cal pointed out).
Otherwise, try one of these:
//substring [1:len]
$yourString = substr($_GET["Submit"], 1);
//replace "#" with ""
$yourString = str_replace("%23", "", $_GET["Submit"], 1); //1 is the limit of #s to remove
//parse the URL, then get the path
$yourString = parse_url($_GET["Submit"], PHP_URL_PATH);
1 Comment
Kevin ver
i get this error : Fatal error: Only variables can be passed by reference in demo.php on line 6
Try this, if you are sure that the first character is either a # or the encoding of one (%23):
<?php echo substr(urldecode($_GET["Submit"]),1); ?>
