I know that when passing strings between functions
char *str is almost the same as char str[n] in function header.
However i do wanna know why this would work and whats the difference between these 2 when working with string
I found that if i declare a "char *in" first then assign a string to it "in=string;" this wont work
can some one tell me whats behind this?
Is there anyway I can assign a array to another array? like in Java
Thanks
char[] one;
char[] two={'a','b'};
one=two;
char[] one;
The syntax is wrong. This isn't Java.
char* one;
char two[]={'a','b'};
one = two;
This works because array decays to a pointer.
"char *str is almost the same as char str[n] in function header."
NO. Arrays and pointers are two different concepts. They both aren't the same.
char *str and char[n] are identical; they both declare str as a pointer. (This applies only to parameters.)Array and Pointer are two different concepts. I guess you should start slowly with basics, this is one paper that explains : http://www.cs.bu.edu/teaching/cpp/string/array-vs-ptr/
std::string, which is a class for handling string. However, you can still use C-style string. In C, string is a concept not a type, an array of character ending with \0 (NULL) character. That's the difference!NULL is a null pointer constant, not a null character.The best explanation I've seen for the relationship between arrays and pointers in C (and C++) is section 6 of the comp.lang.c FAQ.
