How to print the value of a variable in the stack trace

1. You could try to declare a custom exception for debugging value.

class DebuggingValueError(Exception):
    """Exception raised for debugging value.

    Attributes:
        value -- input value which caused the error
        message -- explanation of the error
    """

    def __init__(self, value, message="this value is for debugging"):
        self.value= value
        self.message = message
        super().__init__(self.message)

2. try to catch this exception in the outside of program.

import logging
import sys
logging.basicConfig(stream=sys.stdout, level=logging.DEBUG)
try:
    os.chdir(directoryName)
    ....
    ....
    ....
except Exception as ex:
  logging.exception(ex)
  logging.debug(directoryName)

Two options:

NOTE! Be careful of inadvertently logging PII/sensitive data!

1. https://github.com/andy-landy/traceback_with_variables also looks excellent! Following on,

from traceback_with_variables import prints_exc


@prints_exc
def f(n):
    print(1 / n)


def main():
    f(0)


main()

2. Another option is given here - https://stackoverflow.com/a/26178112/1021819

Copying from there (thanks CadentOrange!),

import sys, traceback, logging

logging.basicConfig(level=logging.ERROR)

try: 
    x = 0 
    y = 1 
    z = y / x 
    z = z + 1 
    print "z=%d" % (z) 
except: 
    logging.exception("Values at Exception: x=%d y=%d " % (x,y))

i.e. logging.exception() gives access to the variables defined within the try block.