Get object out of array if it contains value of another item in another array [duplicate]

Question

I have the following array of objects:

const raceOptions = [
  { value: "AmericanIndianOrAlaskaNative", label: "American Indian or Alaska Native" },
  { value: "AmericanIndianOrAlaskaNativeOther", label: "American Indian or Alaska Native Other" },
  { value: "Asian", label: "Asian" },
  { value: "AsianIndian", label: "Asian Indian" },  
];

I also have another array:

var incomingArray = ['Asian', 'AmericanIndianOrAlaskanPacific', 'NativeHawaiian', 'BlackorAfricanAmerican']

How can I create a new array of objects only if the incomingArray has values that match the raceOptions value?

If incomingArray contains 'Asian' I want a new array that will contain { value: "Asian", label: "Asian" } which comes from the raceOptions array.

Unmitigated · Accepted Answer · 2023-01-18 19:26:14Z

1

Use Array#filter in conjunction with Array#includes.

const raceOptions = [
  { value: "AmericanIndianOrAlaskaNative", label: "American Indian or Alaska Native" },
  { value: "AmericanIndianOrAlaskaNativeOther", label: "American Indian or Alaska Native Other" },
  { value: "Asian", label: "Asian" },
  { value: "AsianIndian", label: "Asian Indian" },

];
let incomingArray = ['Asian', 'AmericanIndianOrAlaskanPacific', 'NativeHawaiian', 'BlackorAfricanAmerican'];
let res = raceOptions.filter(x => incomingArray.includes(x.value));
console.log(res);

answered Jan 18, 2023 at 19:26

Unmitigated

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