how to format a date in shell script

Question

How can i format the date "01-SEP-2011" on "2011-09-01" format in shell script?

Bitmap · Accepted Answer · 2011-09-30 08:39:20Z

6

Try this:

$ date --date='01-SEP-2011' +%Y-%m-%d

edited Sep 30, 2011 at 8:39

Bitmap

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answered Sep 29, 2011 at 20:27

Pabluez

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2 Comments

Keith Thompson Over a year ago

That assumes you have the GNU coreutils version of the date command. If you're running bash, you probably do -- but it might not be installed by default on MacOS, for example. (I don't know whether bash is installed by default, but there's no non-GNU version of bash; there are non-GNU versions of date.)

Keith Thompson Over a year ago

date ... +%F also works (but I think +%Y-%m-%d is a bit more portable).

maerics · Accepted Answer · 2011-09-30 13:53:39Z

1

If you have Ruby installed on the target system you could do this:

#/bin/bash
read DATE # 01-SEP-2011
set DATE=$(ruby -rdate -e "puts Date.parse('$DATE').to_s")
echo $DATE # 2011-09-01

edited Sep 30, 2011 at 13:53

answered Sep 29, 2011 at 20:38

maerics

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Comments

Kent · Accepted Answer · 2011-09-29 21:24:39Z

0

kent$  date +%F -d "01-SEP-2011" 
2011-09-01

answered Sep 29, 2011 at 21:24

Kent

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