bad argument #1 to 'for iterator' (table expected, got string)

Question

have a data like this

result = { 
    [1] = { ["identifier"] = MMK18495,["vehicles"] = {"vehN":"Caracara 4x4","vehM":"caracara2","totals":3},["id"] = 1,} ,
    [2] = { ["identifier"] = MMK18495,["vehicles"] = {"vehN":"Sandking SWB","vehM":"sandking2","totals":3},["id"] = 2,} ,
    [3] = { ["identifier"] = MMK18495,["vehicles"] = {"totals":5,"vehN":"Caracara 4x4","vehM":"caracara2"},["id"] = 3,} ,
    }

trying to sort this data to a menu like this

    for i=1, #result, 1 do
        local ownedcars = result[i].vehicles
        print(dump(ownedcars))
        for _,v in pairs(ownedcars) do  -- <- the error is here
            menu[#menu+1] = {
                header = " Model "..v.vehM.." Name "..v.vehN.." quantity"..v.totals,
                txt = "",
            }
        end
    end

the output of ownedcars

{"vehN":"Caracara 4x4","vehM":"caracara2","totals":3}

but here is the error

That is not a Lua table, looks like you have a string containing a json structure — Nifim
– Nifim, Commented Jan 3, 2023 at 1:51
this is LUA forget about menu table, how to sort vehicles for each ID ? As a result, I would like to receive the following text. id 1 vehicles vehM totals ``` vehM caracara2 - totals 3 vehM sandking2 - totals 3 vehM caracara2 - totals 5 ``` — VPSCoin
– VPSCoin, Commented Jan 3, 2023 at 15:31

dave · Accepted Answer · 2023-01-04 01:36:58Z

0

As others have commented, this is not a Lua table. When inputting JSON tables, Lua reads them as strings. You will first need to convert your given JSON string into Lua. Thankfully, others have already done this. I will refer you to this question which has answers that solved this problem.

Once you've converted your JSON string to a Lua table, you should be good to go.

edited Jan 4, 2023 at 1:36

answered Jan 4, 2023 at 1:36

dave

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