[{name:"abc",value:5},{name:"abc",value:10},{name:"abc1",value:5},{name:"abc1",value:15}]
I want to merge it by name so that the new array will be
[{name:"abc",value:15},{name:"abc1",value:20}]
Can i do it with es6 or a simple function
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5 Answers
Using reduce and without find or findIndex
const data = [{name:"abc",value:5},{name:"abc",value:10},{name:"abc1",value:5},{name:"abc1",value:15}];
const summedDataObj = data.reduce((acc, entry) => {
if (acc[entry.name]) acc[entry.name].value += entry.value;
else acc[entry.name] = entry;
return acc;
}, {});
const summedDataArr = Object.values(summedDataObj);
console.log(summedDataArr);
Comments
you can group the data by name using this function:
function groupBy(arr, prop) {
const map = new Map(Array.from(arr, obj => [obj[prop], []]));
arr.forEach(obj => map.get(obj[prop]).push(obj));
return Array.from(map.values());
}
this yields this result:
[
[
{"name": "abc", "value": 5},
{"name": "abc", "value": 10}
],
[
{"name": "abc1", "value": 5},
{"name": "abc1", "value": 15}
]
]
which can be aggregated by using reduce on each resulting array:
groupedData.map(entry=>entry.reduce((acc,cur)=>({
...acc,
value: acc.value + cur.value
})))
so all together we get:
function groupBy(arr, prop) {
const map = new Map(Array.from(arr, obj => [obj[prop], []]));
arr.forEach(obj => map.get(obj[prop]).push(obj));
return Array.from(map.values());
}
const data = [{name:"abc",value:5},{name:"abc",value:10},{name:"abc1",value:5},{name:"abc1",value:15}]
const aggregatedData = groupBy(data,"name")
.map(entry=>entry.reduce((acc,cur)=>({
...acc,
value:acc.value+cur.value
})))
Comments
const obj = [{name:"abc",value:5},{name:"abc",value:10},{name:"abc1",value:5},{name:"abc1",value:15}]
arr = obj.reduce((obj, item) => {
let find = obj.find(i => i.name === item.name && i.date === item.date);
let _d = {
...item
}
find ? (find.value += item.value ) : obj.push(_d);
return obj;
}, [])
console.log(arr);
Comments
const data = [{
name: "abc",
value: 5
},
{
name: "abc",
value: 10
},
{
name: "abc1",
value: 5
},
{
name: "abc1",
value: 15
},
];
const groupArr = data.reduce((r, a) => {
const idx = r.findIndex((el) => el.name === a.name);
idx === -1 ? r.push(a) : (r[idx].value += a.value);
return r;
}, []);
console.log(groupArr);
Comments
You can achieve this with the help of Array#reduce method.
Live Demo :
const arr = [{name:"abc",value:5},{name:"abc",value:10},{name:"abc1",value:5},{name:"abc1",value:15}];
const res = arr.reduce((obj, curr) => {
if (obj.hasOwnProperty(curr.name) && obj[curr.name].name === curr.name) {
obj[curr.name].value += curr.value
} else {
obj[curr.name] = curr;
}
return obj
}, {});
console.log(Object.values(res));