Why program run for infinite times for character?

Question

#include <stdio.h>

int main() {
  int n;

  do {
    printf("Enter a Number :");

    scanf("%d", &n);

    printf("%d \n", n);

    if (n % 7 == 0) {
      break;
    }
  } while (1);

  printf("Program Ends");

  return 0;
}

Why the problem run for infinite time for input of any character?

I want to know why it is happening? It should break from the loop because character is not divisible by 7?

Check return value of scanf. Read from docs (like, just google "C scanf") what the return value means. — hyde
– hyde, Commented Nov 24, 2022 at 18:09
Does this answer your question? Why is scanf() causing infinite loop in this code? — OznOg
– OznOg, Commented Nov 24, 2022 at 18:11

Stack Exchange Broke The Law · Accepted Answer · 2022-11-24 18:09:24Z

1

It doesn't read a character. This call: scanf("%d", &n); doesn't do anything because there is no number to read. It returns 0 to let you know it didn't read a number, but you don't check.

answered Nov 24, 2022 at 18:09

Stack Exchange Broke The Law

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