Trying to find element ('href') with Selenium in Python

Question

I am trying to get the URL ('href') of the below element in Python with Selenium. For the life of me it is not working, this is the only output I get is as an example:

NoSuchElementException: Message: no such element: Unable to locate element: {"method":"xpath","selector":"//*[@id="href"]"}

This is the element I want to get the ('Href') or ('Text') from:

code.private.pri

Selector: #tinymce > p:nth-child(20) > a

Xpath: //*[@id="tinymce"]/p[7]/a

Full Xpath: /html/body/p[7]/a

I tried the following methods to find the element on the page with no luck:

Selector Xpath Full Xpath

Only get: NoSuchElementException: Message: no such element: Unable to locate element:

This is the path when inspecting the elekent on the webpage: <p> <a href="code.private.pri">https://code.private.pri</a> </p> — Almar Fivaz
– Almar Fivaz, Commented Nov 11, 2022 at 13:58

AbiSaran · Accepted Answer · 2022-11-11 14:05:22Z

0

You have to use 'get_attribute()' function to get the urls:

For example, if this XPath is correct - '//*[@id="tinymce"]/p[7]/a', then locator should be like this:

driver.fine_element(By.XPATH, "//*[@id='tinymce']/p[7]/a").get_attribute("href")

answered Nov 11, 2022 at 14:05

AbiSaran

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2 Comments

Almar Fivaz Over a year ago

Thank you for the response, tried you suggestion but unfortunately, it's also not working: NoSuchElementException: Message: no such element: Unable to locate element: {"method":"xpath","selector":"//*[@id='tinymce']/p[7]/a"}

AbiSaran Over a year ago

Your locator is wrong, use the correct locator.

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