How to use single loop to obtain the given sequence?

Question

I want to use just 1 loop in python to obtain the sequence like (likes counter in second and miliseconds)

0 0.033 0.066 0.1 0.133 0.166 0.2....

Currently, I have to use two loops to obtain it as follows

miliseconds =[0 0.033 0.066 0.1 0.133 0.166 0.2 0.233 0.266 0.3 0.333 0.366 0.4 0.433 0.466 0.5 0.533 0.566 0.6 0.633 0.666 0.7 0.733 0.766 0.8 0.833 0.866 0.9 0.933 0.966 1]
for second in range(100):
   for milisecond_ in miliseconds:
       print (second + milisecond_)

0.033 milliseconds is 33 microseconds. Deal with integers as much as possible when programming. — chepner
– chepner, Commented Nov 1, 2022 at 20:31

Mahdi F. · Accepted Answer · 2022-11-01 20:12:25Z

3

Use mathematics:

# You can change second to '100'
second = 3
for i in range((30 * second)+1):
    print(round(i/30, 4))
    
    # If you want to get full precision -> uncomment below line
    # print(i/30)

Output:

edited Nov 1, 2022 at 20:12

answered Nov 1, 2022 at 20:09

Mahdi F.

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6 Comments

azro Over a year ago

A round(i, 4) could be nice with that

Mark Ransom Over a year ago

@azro rounding wouldn't produce the exact numbers given in the question. Better to leave them with full precision or use a custom truncation function.

Moon Lee Over a year ago

Great solution. However if I just want to print number like x.033 x.066 x.1 where x is second instead of x.0333 x.0667 x.1. Is it possible to do it?

Mahdi F. Over a year ago

@MoonLee, maybe change print(round(i/30, 4)) -> print(round(i/30, 3)). Are you wanting this?

Moon Lee Over a year ago

Round 3 will gives 0.067 instead of 0.066

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