hexadecimal to strings using python

Question

i am new to python and trying to convert a list of hexadecimal to string

chunk= [' ho', 'w a', 're ', 'you']
chunk_2 = [i.encode('utf-8').hex() for i in chunk]
print(chunk_2)
['20686f', '772061', '726520', '796f75']

chunk_3 = [int(i, base=16) for i in chunk_2]
print(chunk_3)
[2123887, 7807073, 7496992, 7958389]
(convert chunk_3 to hexadecimal)

chunk_4 = [f'{i:x}' for i in chunk_3]
print (chunk_4)
['20686f', '772061', '726520', '796f75']

how can i convert hexadecimal chunk_4 back to list of string inchunk

Tim Roberts · Accepted Answer · 2022-10-20 19:17:30Z

2

You can use bytearray for this.

>>> chunk_4 = ['20686f', '772061', '726520', '796f75']
>>> [bytes.fromhex(k).decode() for k in chunk_4]
[' ho', 'w a', 're ', 'you']

edited Oct 20, 2022 at 19:17

answered Oct 20, 2022 at 19:12

Tim Roberts

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4 Comments

wim Over a year ago

bytes.fromhex probably more usual, since we don't need a mutable bytearray here.

Tim Roberts Over a year ago

Good point. My Google search came up with the bytesarray example, so I just copied it.

SEUN Over a year ago

@TimRoberts can you please check to see why i get error (UnicodeDecodeError: 'utf-8' codec can't decode byte 0xf9 in position 2: invalid start byte)

Tim Roberts Over a year ago

That says you are trying to translate strings that are not in UTF-8. You can remove the .decode() to see the 8-bit version. If you know what character you expected it to be, you can figure out what code page you're using and how to do the decode.

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