String Array insertion problem

Question

I want to create a string array where user will give the input and data will be stored in array..I have no clue how to do that-(I read several C books) Any help ll be appreciated What I tried so far:

int choice;
    printf("enter the number of the strings: ");
    scanf("%d",&choice);
char **str=(char **)malloc(100);
    int i;



    for(i=0;i<choice;i++)
    {
        printf("enter %dth element ",i+1);
            str[i]=(char *)malloc(10);
        scanf("%s",str[i]);
    }
    printf("%s",str[0]);

You just need to read more I guess, this is very basic and basic skills will enable you to do it. — Seth Carnegie
– Seth Carnegie, Commented Sep 13, 2011 at 2:14
I should hope it terminates! I'd hate to run a program that I expect to terminate and it just goes on forever. — Chris Lutz
– Chris Lutz, Commented Sep 13, 2011 at 2:17

Lipika Deka · Accepted Answer · 2011-09-13 02:19:10Z

1

You will have to allocate and initialize space for each string before reading them in. If you know he length of your input string then malloc/calloc that much space else guess a size but that would be wastage of space.

for(i=0;i<choice;i++)
     {
         printf("enter %dth element ",i+1);
         str[i] = malloc(sizeof(char)*length);
         memset(str[i],0,length);
         scanf("%s",str[i]);
     }

answered Sep 13, 2011 at 2:19

Lipika Deka

3,9447 gold badges46 silver badges58 bronze badges

Sign up to request clarification or add additional context in comments.

3 Comments

Jonathan Weatherhead Over a year ago

Yeah dynamic allocation is the way to go. But usually when you are doing input like this you do not know the size of the string, so some large buffer is used, copied, and flushed.

learning_bee Over a year ago

str[i] = malloc(sizeof(char)*length); this line does not work!

Lipika Deka Over a year ago

you will have to specify the "length" ...but what Jonathan suggests is the way to go.

K-ballo · Accepted Answer · 2011-09-13 02:15:46Z

1

You are not allocating any spaces for the strings. If you are ok with bounded arrays you could define str as char str[100][128] to have 100 strings up to 128 chars each. At least until you learn some basic dynamic allocation.

answered Sep 13, 2011 at 2:15

K-ballo

81.6k20 gold badges165 silver badges172 bronze badges

1 Comment

learning_bee Over a year ago

i know dynamic allocation-I can do that

Jonathan Weatherhead · Accepted Answer · 2011-09-13 02:18:52Z

0

If I am reading this correctly, you have defined a pointer to an array of 100 chars. What you really want is 'choice' arrays of length 100 of chars I think char str[choice][100]

and then you can use your array as you have for the reading and printing of string input.

answered Sep 13, 2011 at 2:18

Jonathan Weatherhead

1,5909 silver badges11 bronze badges

Collectives™ on Stack Overflow

String Array insertion problem

3 Answers 3

3 Comments

1 Comment

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

3 Comments

1 Comment

Comments

Your Answer

Sign up or log in

Post as a guest

Related